All categories

2 years ago

What is 101,949 rounded to the nearest hundred thousand?

Mathematics

2 answers:

Maslowich2 years ago

6 0

Answer:

The nearest hundred thousand of the provided number 101,949 is 100,000.

Step-by-step explanation:

Consider the provided number 101,949.

Rule of rounding a number is:

If 0, 1, 2, 3, or 4 follow the number, then no need to change the rounding digit.

If 5, 6, 7, 8, or 9 follow the number, then rounding digit rounds up by one number.

Here, the number at the ten thousand place is 0, so no need to change the rounding digit.

Thus, the number can be rounded to the nearest hundred thousand is shown as:

100,000

The nearest hundred thousand of the provided number 101,949 is 100,000.

kobusy [5.1K]2 years ago

5 0

Well the answer is 103,000 because when you round it the 1 becomes a 2

You might be interested in

What is 5 raised to the 5th power?

Roman55 [17]

Five raised to the fifth power 5^5 5*5*5*5*5 = 3,125

8 0

3 years ago

Read 2 more answers

A radio is being discounted 40%. If the sale price of the radio is $31.02, what was the original price of the radio?

kobusy [5.1K]

Answer:

$51.70 is the original price

Step-by-step explanation:

Step 1:

Turn 40% into a decimal which makes it 0.40

ex. 50% would be 0.50, 5% would be 0.05 etc.

Step 2:

Put the numbers into this formula: Original Price (x) - Percent Off times Original Price = Sales Price

x - 0.40x = 31.02 this is basically 1x - 0.40x = 31.02 so,

Solving the left side of our equation gives us 1x - 0.40x = 0.60x

so now you have: 0.60x = 31.02

Step 3:

Divide both sides by 0.60 which gets x by itself and gives us the original price which is $51.70

8 0

2 years ago

AD<br>What is the value of the expression ( 2 ^4)^2

Len [333]

I believe the value is 256
If you square 2 four times you will get 16
If you if you square 16 by two you will get 256 as your answer. Hope this helps!

7 0

2 years ago

Read 2 more answers

Find the sum of the given arithmetic series. 14 + 28 + 42 + 56 + ... + 280

cricket20 [7]

14 + 28 + 42 + 56 + … 280

= 14 (1 + 2 + 3 + 4 + … + 20)

= 14 × 20 × 21 / 2

= 2940

where we use the well-known identity,

$\displaystyle \sum_{i=1}^ni = 1 + 2 + 3 + \cdots + n = \dfrac{n(n+1)}2$

6 0

3 years ago

Solve for X. 11x+10=180

Ilia_Sergeevich [38]

X = 170/11
H0P3 It H3LPS :)

7 0

3 years ago

Read 2 more answers