sin 45 = opp/hyp
sin 45 = 4 / y
y = 4/sin 45
y = 4 /((sqrt2)/2)=4* sqrt(2)
tan 45 =opp/adj
tan 45 = 4/(x-3)
1 = 4/(x-3)
x-3 = 4
x=7
B

so... notice the example there, with 8
so.. you tell us, what is the relationship then?
Answer:
256
Step-by-step explanation:
Hope this helps!
If not, I am sorry.
To take out terms outside the radical we need to divide the power of the term by the index of the radical; the quotient will be the power of the term outside the radical, and the remainder will be the power of the term inside the radical.
First, lets factor 8:
Now we can divide the power of the term, 3, by the index of the radical 2:

= 1 with a remainder of 1
Next, lets do the same for our second term

:

= 3 with a remainder of 1
Again, lets do the same for our third term

:

with no remainder, so this term will come out completely.
Finally, lets take our terms out of the radical:

We can conclude that the correct answer is the third one.