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jeyben [28]
3 years ago
10

Help please Please I need help

Mathematics
1 answer:
Ipatiy [6.2K]3 years ago
6 0

Answer:

D. -2 and 6

Step-by-step explanation:

Use the quadratic formula to put either -2 or 6 in and get it to equal 0.

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A train ticket cost $14 .Don paid with $20 bill .How much money should he get back
Crazy boy [7]

Answer:

$6

Step-by-step explanation:

$20-$14=$6

3 0
3 years ago
Read 2 more answers
An item that is 20% off is sold for 48$ what was the original price
solniwko [45]

Answer:

9.6

trust me I double checked and everything

7 0
3 years ago
Please help me!! i don’t understand this like at all this is algebra btw
gladu [14]

The length and width of the fence should be made 76.25 feet and 23.75 feet respectively. Also, the expression for the length is L = 3W + 5 and the perimeter is P = 2(4W + 5).

<h3>How to determine the fence's dimension?</h3>

Mathematically, the perimeter of a rectangle can be calculated by using this formula;

P = 2(L + W)

<u>Where:</u>

  • P is the perimeter of a rectangle.
  • L is the length of a rectangle.
  • W is the width of a rectangle.

Since the length of this fence is 5 more than 3 times the width, we have:

L = 3W + 5

Substituting the given parameters into the formula, we have;

200 = 2(3W + 5 + W)

200 = 2(4W + 5)

200 = 8W + 10

8W = 190

W = 190/8

W = 23.75 feet.

For the length, we have:

L = 3W + 5

L = 3(23.75) + 5

L = 76.25 feet.

Read more on perimeter of a rectangle here: brainly.com/question/17107023

#SPJ1

5 0
2 years ago
The perimeter of the original rectangle is ______
sergey [27]

Answer:

  • perimter of original rectangle = <u>17. 6 mm</u>
  • side length of the enlarged rectangle = <u>23. 22 mm</u>
  • perimeter of the enlarged rectangle = <u>95. 04 mm</u>

Step-by-step explanation:

<u>PERIMETER</u><u> </u><u>OF</u><u> </u><u>ORIGINAL</u><u> </u><u>RECTANGLE</u>

  • Length of original rectangle = 4.5 mm
  • Width of original rectangle = 4.3 mm

<em>perimeter = 2 × ( length + width)</em>

= 2 × ( 4.5 + 4.3)

= 2 × 8.8

= 17. 6 mm

<u>SIDE</u><u> </u><u>LENGTH</u><u> </u><u>OF</u><u> </u><u>ENLARGED</u><u> </u><u>RECTANGLE</u>

  • Width of original rectangle = 4. 5 mm
  • Width of enlarged rectangle = 24.3 mm

Enlargement factor = 24.3 / 4.5

= 5.4

  • Length of original rectangle = 4.5 mm
  • Enlargement factor = 5.4

Side length of enlarged rectangle

= original length × Enlargement factor

= 4.3 × 5.4

= 23. 22 mm

<u>PERIMTER OF ENLARGED RECTANGLE</u>

= 2 × ( enlarged ength + enlarged breadth)

= 2 × (23. 22 + 24. 3 )

= 95. 04 mm

8 0
3 years ago
Find the work done by force dield f(x,y)=x^2i+ye^xj on a particle that moves along parabola x=y^2+1 from(1,0) to (2,1)
NemiM [27]
Call the parabola P, parameterized by \mathbf r(y)=\langle y^2+1,y\rangle with 0\le y\le 1\rangle. Then the work done by \mathbf f(x,y) along P is

\displaystyle\int_P\mathbf f(x,y)\cdot\mathrm d\mathbf r=\int_{y=0}^{y=1}\mathbf f(x(y),y)\cdot\dfrac{\mathrm d\mathbf r(y)}{\mathrm dy}\,\mathrm dy
=\displaystyle\int_0^1\langle(y^2+1)^2,ye^{y^2+1}\rangle\cdot\langle2y,1\rangle\,\mathrm dy
=\displaystyle\int_0^1(2y^5+4y^3+2y+ye^{y^2+1})\,\mathrm dy=\frac73-\frac e2+\frac{e^2}2
8 0
4 years ago
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