$\cos 2\theta=2\cos^2 \theta-1=\frac{12}{13}\\\\2\cos^{2} \theta=\frac{25}{13}\\\\\cos^{2} \theta=\frac{25}{26}\\\\\boxed{\cos \theta=\frac{5}{\sqrt{26}}}$

(Note I took the positive case since $\theta$ terminates in the first quadrant)

Using the Pythagorean identity,

$\sin^2 \theta+\cos^2 \theta=1\\\\\sin^2 \theta+\frac{25}{26}=1\\\\sin^2 \theta=\frac{1}{26}\\\\\boxed{\sin \theta=\frac{1}{\sqrt{26}}}$

(Note I took the positive case since $\theta$ terminates in the first quadrant)

6 0

1 year ago

. what is the difference between these 16 degrees farenheit and -15 degrees farenheit

Ivahew [28]

Answer:

The answer 1 degrees Fahrenheit because you have to subtract 16-15. I subtracted 16-15 instead of putting the negative sign

7 0

3 years ago

SO Problem -3.62 + 18.57 =

Whitepunk [10]

Answer:

___________________

5 0

3 years ago