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mamaluj [8]
2 years ago
14

Look at picture!!!Please help I’m completely lost and behind on work. pLEase HELP ME!

Mathematics
1 answer:
Rasek [7]2 years ago
3 0

Answer:

i think it is x= -7 and x=1

Step-by-step explanation:

i can't understand it clearly but i can sure its number 1 or letter A

I HOPE I'M RIGHT HEHE

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Simplify the difference quotient f ( x + h ) â f ( x ) h for the function f ( x ) = 6 x â x 2
ladessa [460]

Answer:

final answer is 6

Step-by-step explanation:

Given f(x)=6x-2

To find the difference quotient use formula

\frac{f(x+h)-f(x)}{h}

f(x)=6x-2

f(x+h)=6(x+h)-2=6x+6h-2

Now plug it in the formula

\frac{f(x+h)-f(x)}{h}

\frac{6x+6h-2-(6x-2)}{h}

\frac{6x+6h-2-6x+2)}{h}

\frac{6h}{h}

6

5 0
3 years ago
Taylor got an Ulta gift card that had $20 on it. If she bought 3 lipsticks at $2.99 each
Vadim26 [7]

$6.44 is left

Hope this helps! :D

4 0
3 years ago
Read 2 more answers
Suppose a basketball player has made 231 out of 361 free throws. If the player makes the next 2 free throws, I will pay you $31.
statuscvo [17]

Answer:

The expected value of the proposition is of -0.29.

Step-by-step explanation:

For each free throw, there are only two possible outcomes. Either the player will make it, or he will miss it. The probability of a player making a free throw is independent of any other free throw, which means that the binomial probability distribution is used to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

In which C_{n,x} is the number of different combinations of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

And p is the probability of X happening.

Suppose a basketball player has made 231 out of 361 free throws.

This means that p = \frac{231}{361} = 0.6399

Probability of the player making the next 2 free throws:

This is P(X = 2) when n = 2. So

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 2) = C_{2,2}.(0.6399)^{2}.(0.3601)^{0} = 0.4095

Find the expected value of the proposition:

0.4095 probability of you paying $31(losing $31), which is when the player makes the next 2 free throws.

1 - 0.4059 = 0.5905 probability of you being paid $21(earning $21), which is when the player does not make the next 2 free throws. So

E = -31*0.4095 + 21*0.5905 = -0.29

The expected value of the proposition is of -0.29.

3 0
3 years ago
Hellppp i’ll give brainliest
Papessa [141]

The hypotenuse is the side opposite to the right angle.

B.) opposite

5 0
2 years ago
How to calculate flow rate?​
klemol [59]
I think it’s B because 0.25x4=1 L/S
3 0
2 years ago
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