Answer:
Explanation:
Using the formula for calculating range expressed as;
R = U√2H/g
U is the speed = 300m/s
H is the maximum height = 78.4m
g is the acceleration due to gravity = 9.8m/s²
Substitute into the fromula;
R = 300√2(78.4)/9.8
R = 300 √(16)
R = 300*4
R = 1200m
Hence the projectile travelled 1200m before hitting the ground
Answer:
A : hot and moist, maritime tropical
B: cold and dry, maritime polar
C: hot and moist , maritime tropical
D: cold and dry, continental polar
E: hot and moist , maritime tropical
F: cold and dry , maritime polar
Explanation:
Cold air is denser than warm air. The more water vapor that is in the air, the less dense the air becomes. That is why cold, dry air is much heavier than warm, humid air.
Maritime polar (mP) air masses are cool, moist, and unstable. Some maritime polar air masses originate as continental polar air masses over Asia and move westward over the Pacific, collecting warmth and moisture from the ocean.
Maritime tropical (mT) air masses are warm, moist, and usually unstable.
Answer:
The x-component of 
is 56.148 newtons.
Explanation:
From 1st and 2nd Newton's Law we know that a system is at rest when net acceleration is zero. Then, the vectorial sum of the three forces must be equal to zero. That is:
(1)
Where:
, 
, 
- External forces exerted on the ring, measured in newtons.
- Vector zero, measured in newtons.
If we know that ![\vec F_{1} = (70.711,70.711)\,[N]](https://tex.z-dn.net/?f=%5Cvec%20F_%7B1%7D%20%3D%20%2870.711%2C70.711%29%5C%2C%5BN%5D)
, ![\vec F_{2} = (-126.859, 46.173)\,[N]](https://tex.z-dn.net/?f=%5Cvec%20F_%7B2%7D%20%3D%20%28-126.859%2C%2046.173%29%5C%2C%5BN%5D)
, 
and ![\vec O = (0,0)\,[N]](https://tex.z-dn.net/?f=%5Cvec%20O%20%3D%20%280%2C0%29%5C%2C%5BN%5D)
, then we construct the following system of linear equations:
(2)
(3)
The solution of this system is:
, 
The x-component of is 56.148 newtons.
I’m not sure maybe attach a image or something
That volocity is about how it moves not how fast it goes
