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Mademuasel [1]
2 years ago
12

Two positive point charges are 4.9cm apart. If the electric potential energy is 70.0 μJ, what is the magnitude of the force betw

een the two charges?
Physics
1 answer:
ExtremeBDS [4]2 years ago
6 0

Hi there!

Recall the following:

V \text{ (Electric Potential Energy) } = \frac{kq_1q_2}{r}\\\\F_E = \frac{kq_1q_2}{r^2}

k = Coulomb's Constant (Jm/C²)

q = Charge (C)
r = distance between charges (m)

To calculate the electric force between the two charges, we can simply divide by another 'r' (distance):

F_E = \frac{70}{0.049} = \boxed{1428.57 \mu J}

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5 0
3 years ago
A penny is placed on a rotating turntable. where on the turntable does the penny require the largest centripetal force to remain
Mama L [17]

m = mass of the penny

r = distance of the penny from the center of the turntable or axis of rotation

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F = centripetal force experienced by the penny

centripetal force "F" experienced by the penny of "m" at distance "r" from axis of rotation is given as

F = m r w²

in the above equation , mass of penny "m"  and angular speed "w" of the turntable is same at all places. hence the centripetal force directly depends on the radius .

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4 0
3 years ago
How does uncertainty relate to measurements and calculations made during an investigation?
Rom4ik [11]

there here is your answer to your question

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3 0
2 years ago
The unit of electric potential or electromotive force is the
goldenfox [79]

Answer:

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3 0
3 years ago
A gas sample is held at constant pressure. The gas occupies 3.62 L of volume when the temperature is 21.6°C. Determine the tempe
Serhud [2]

Answer:

281 K

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Charles's Law. V1/T1 = V2/T2.

The temperature must be in K = 21.6°C + 273 = 294.6K.

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6 0
2 years ago
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