All categories

2 years ago

If the speedometer of a car reads 5 mph, does it mean it is going at a constant speed?

Physics

1 answer:

marshall27 [118]2 years ago

5 0

Answer:

Yes

Explanation:

if it's staying at 5mph and cruising at that speed it's constant speed

You might be interested in

A train travels north at a speed of 50 m/s.

Gala2k [10]

The apparent velocity is B) 48 m/s north

Explanation:

Here we have a problem of relativity of velocities.

In fact, the train is travelling north at a speed of

$v_t = 50 m/s$

where this velocity is measured with respect to the ground.

At the same time, a passenger on the train is walking towards the rear (so, south) at a velocity of

$v'=2 m/s$

where this velocity is measured with respect to the train, which is in motion in the opposite direction.

Therefore, the apparent velocity of the passenger with respect to an observer standing on the ground is:

$v=V_t - v' = 50 - 2 = 48 m/s$

And the direction is north, since this number is positive.

Learn more about velocity:

brainly.com/question/5248528

#LearnwithBrainly

8 0

3 years ago

In a candy factory, the nutty chocolate bars contain 20.0 % pecans by mass. If 4.0 kg of pecans were used for candy last Tuesday

ladessa [460]

Answer:

44.09 pounds

Explanation:

We got that 20 % of the mass of a nutty chocolate bar its pecans, if 4.0 kg of pecans were used, we need to find the X in the equation

$0.2 * X = 4.0 \ kg$

where X its the total mass of nutty chocolate bars produced. So, we can just divide by 0.2 on both sides, and we find:

$X = 4.0 kg / 0.2$

$X = 20.0 \ kg$

Of course, we need the total mass produced in pounds, and not in kilograms. Looking at an conversion table, we can find that 1 kg its 2.20462 pounds, multiplying the value for total mass produced by the conversion factor we get:

$X = 20.0 \ kg * 2.20462 \ \frac{pounds}{kg}$

$X = 44.0924 \ pounds$

Now, we just need to round off to two significant figures. This is:

$X = 44.09 \ pounds$ ,

the total mass of nutty chocolate bars made last Tuesday to two significant figures.

5 0

3 years ago

Definition for compression and rarefraction

s344n2d4d5 [400]

Compression and rarefaction are two phenomenon occurs in longitudunal wave!

when there is denser particle gathering in that wave , there we called it compression and the rarer part of particles is rarefaction !

6 0

2 years ago

Read 2 more answers

The temperature inside my refrigerator is about 4 degrees C. If I place a balloon in my fridge that initially has a temperature

maksim [4K]

Convert the given temperatures from celsius to kelvin since we are dealing with gas.

To convert to kelvin, add 273.15 to the temperature in celsius.

T1 = 22 + 273.15 = 295.15 k

T2 = 4 + 273.15 = 277.15 k

V1 = 0.5 L

Let's find the final volume (V2).

To solve for V2 apply Charles Law formula below:

$\frac{V_1}{T_1}=\frac{V_2}{T_2}$

5 0

8 months ago

A 2 m tall, 0.5 m inside diameter tank is filled with water. A 10 cm hole is opened 0.75 m from the bottom of the tank. What is

valina [46]

Answer:

4.75 m/s

Explanation:

The computation of the velocity of the existing water is shown below:

Data provided in the question

Tall = 2 m

Inside diameter tank = 2m

Hole opened = 10 cm

Bottom of the tank = 0.75 m

Based on the above information, first we have to determine the height which is

= 2 - 0.75 - 0.10

= 2 - 0.85

= 1.15 m

We assume the following things

1. Compressible flow

2. Stream line followed

Now applied the Bernoulli equation to section 1 and 2

So we get

$\frac{P_1}{p_g} + \frac{v_1^2}{2g} + z_1 = \frac{P_2}{p_g} + \frac{v_2^2}{2g} + z_2$

where,

P_1 = P_2 = hydrostatic

z_1 = 0

z_2 = h

Now

$\frac{v_1^2}{2g} + 0 = \frac{v_2^2}{2g} + h\\\\V_2 < < V_1 or V_2 = 0\\\\Therefore\ \frac{v_1^2}{2g} = h\\\\v_1^2 = 2gh\\\\ v_1 = \sqrt{2gh} \\\\v_1 = \sqrt{2\times 9.8\times 1.15}$

= 4.7476 m/sec

= 4.75 m/s

6 0

2 years ago