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BartSMP [9]
2 years ago
11

An Elevator of mass 200 kg travels upwards at constant velocity. What is the tension in the cables?

Physics
1 answer:
I am Lyosha [343]2 years ago
8 0

The tension in the cables as the elevator travel upwards is 1,960 N.

The given parameters:

  • Mass of the elevator, m = 200 kg

<h3>Newton's second law of motion;</h3>

Newton's second law of motion states that the force applied to an object is directly proportional to the product of mass and acceleration of the object.

The tension in the cables as the elevator travel upwards is calculated by applying Newton's second law of motion as shown below;

T = ma + mg

where;

  • a is the acceleration of the elevator
  • g is the acceleration due to gravity

At constant velocity, acceleration is zero (a = 0)

T = m(0) + mg

T = mg

T = 200 x 9.8

T= 1,960 N

Thus, the tension in the cables as the elevator travel upwards is 1,960 N.

Learn more about Newton's second law here: brainly.com/question/3999427

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A super ball is dropped from a height of 100 feet. Each time it bounces, it rebounds half the distance it falls. How many feet w
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The total distance travelled by the ball after the fourth impact is 275 feet.

<u>Explanation:</u>

Given-

Height, h = 100 feet

Rebounds half the distance

Distance in feet for the fourth time, x = ?

For the first time, the distance travelled by the ball is, x = 100 feet

For the second time, it will bounce up to 50 feet and fall upto 50 feet( half of 100 feet)

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For the third time, it will bounce up to 25 feet and fall upto 25 feet( half of 50 feet)

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For the fourth time, it will bounce up to 12.5 feet and fall upto 12.5 feet( half of 25 feet)

So, the distance travelled after the fourth impact, x = 250 + 12.5 + 12.5 = 275 feet

Therefore, total distance travelled by the ball after the fourth impact is 275 feet.

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Two balls of mass m1 and m2, with velocities v1 and v2 collide head on. Is there any way for both balls to have zero velocity af
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Answer:

Explanation:

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In Inelastic collision both the bodies must stick together as final velocity is zero for both the bodies.

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You connect a 100-resistor, a 800-mH inductor, and a 10.0-uF capacitor in series across a 60.0-Hz, 120-V (peak) source. The impe
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Answer:

Impedance, Z = 107 ohms

Explanation:

It is given that,

Resistance, R = 100 ohms

Inductance, L=800\ mH=800\times 10^{-3}\ H=0.8\ H

Capacitance, C=10\ \mu F=10\times 10^{-6}\ F=10^{-5}\ F

Frequency, f = 60 Hz

Voltage, V = 120 V

The impedance of the circuit is given by :

Z=\sqrt{R^2+(X_C-X_L)^2}...........(1)

Where

X_C is the capacitive reactance, X_C=\dfrac{1}{2\pi fC}

X_C=\dfrac{1}{2\pi \times 60\times 10^{-5}}=265.65\ \Omega

X_L is the inductive reactance, X_L={2\pi fL}

X_L={2\pi \times 60\times 0.8}=301.59\ \Omega

So, equation (1) becomes :

Z=\sqrt{(100)^2+(265.65-301.59)^2}

Z = 106.26 ohms

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So, the impedance of the circuit is 107 ohms. Hence, this is the required solution.

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