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Irina18 [472]
3 years ago
15

The force on an object is given by the equation F = ma. In this equation, F is the force, m is the mass, and a is the accelerati

on. What is the force on an object that has a mass of 540 kg and an acceleration of 2.3 m/s^2?
Physics
1 answer:
Bumek [7]3 years ago
5 0

Answer:

The correct answer is 1242 N

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Which process usually requires water?A.Physical weatheringB.ErosionC.Mass wastingD.Chemical weathering
MAXImum [283]

Answer:

B erosion

Explanation:

Erosion would usually require water

8 0
2 years ago
Which best describes a circuit in series?
Tpy6a [65]
A circuit which only has one path for current to follow
6 0
3 years ago
Suppose the conducting wire (with resistance R) was replace with one of the same material but has its dimension doubled (the len
sveticcg [70]
Resistance of a wire is directly proportional to its length and inversely proportional to the square of its radius.
Thus, if the length is doubled, and the radius is halved:
R₂ = 2R₁/(1/2)²
R₂ = 8R₁
Therefore the resistance increases eight times.
6 0
3 years ago
At noon, ship A is 140 km west of ship B. Ship A is sailing east at 30 km/h and ship B is sailing north at 25 km/h. How fast (in
Luba_88 [7]

Answer:

The rate of change of distance between the two ships is 18.63 km/h

Explanation:

Given;

distance between the two ships, d = 140 km

speed of ship A = 30 km/h

speed of ship B = 25 km/h

between noon (12 pm) to 4 pm = 4 hours

The displacement of ship A at 4pm = 140 km - (30 km/h x 4h) =

140 km - 120 km = 20 km

(the subtraction is because A is moving away from the initial position and the distance between the two ships is decreasing)

The displacement of ship B at 4pm = 25 km/h x 4h = 100 km

Using Pythagoras theorem, the resultant displacement of the two ships at 4pm is calculated as;

r² = a²   +  b²

r² = 20²  +  100²

r = √10,400

r = 101.98 km

The rate of change of this distance is calculated as;

r² = a²   +  b²

r = 101.98 km, a = 20 km, b = 100 km

2r(\frac{dr}{dt} ) = 2a(\frac{da}{dt} )  + 2b(\frac{db}{dt} )\\\\r(\frac{dr}{dt} ) = a(\frac{da}{dt} )  + b(\frac{db}{dt} )\\\\101.98(\frac{dr}{dt} ) = 20(-30 )  + 100(25 )\\\\101.98(\frac{dr}{dt} ) = -600 + 2,500\\\\101.98(\frac{dr}{dt} ) = 1900\\\\\frac{dr}{dt}  = \frac{1900}{101.98} = 18.63 \ km/h

5 0
3 years ago
PLEASE HELP ME WITH THIS ONE QUESTION
PolarNik [594]

OPTION C is the correct answer.

6 0
3 years ago
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