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3 years ago

What is the volume of 43.7 g of helium at stp?

2 answers:

0 0

Answer is: volume of helium is 244.72 liters.
m(He) = 43.7 g.
n(He) = m(He) ÷ M(He).
n(He) = 43.7 g ÷ 4 g/mol.
n(He) = 10.925 mol.
V(He) = n(He) · n(He).
V(He) = 10.925 mol · 22.4 L/mol.
V(He) = 244.72 L.
Vm - molar volume at STP.
n - amount of substance.

egoroff_w [7]3 years ago

0 0

Answer : The volume of helium gas is, 244.72 liters

Explanation : Given,

Mass of helium gas = 43.7 g

Molar mass of helium gas = 4 g/mole

As we know that at STP, 1 mole of gas contains 22.4 liter volume of gas.

First we have to calculate the moles of helium gas.

$\text{Moles of He}=\frac{\text{Mass of He}}{\text{Molar mass of He}}=\frac{43.7g}{4g/mole}=10.925mole$

Now we have to calculate the volume of helium gas.

As, 1 mole of helium gas contains 22.4 liter volume of gas

So, 10.925 mole of helium gas contains $10.925\times 22.4=244.72$ liter volume of gas

Therefore, the volume of helium gas is, 244.72 liters

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