The balanced equation for the reaction is as follows; HCl + KOH ---> KCl + H₂O stoichiometry of HCl to KOH is 1:1 number of KOH moles reacted - 1 mol/L x 0.025 L = 0.025 mol according to 1:1 molar ratio number of KOH moles reacted = number of HCl moles reacted therefore number of HCl moles reacted - 0.025 mol
molarity of HCl is 0.45 M since 0.45 mol are in 1000 mL therefore 0.025 mol are in a volume of 0.025 mol / 0.45 mol/L = 55.5 mL 55.6 mL of HCl is required to neutralise
We can use to formula . Here, N(A) is the final amount. N0 is the initial amount. t is the time elapsed, and is the half life. Plugging in, we get the answer above.