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jarptica [38.1K]
3 years ago
10

Determine the dissociation constants for the following acids. Express the answers in proper scientific notation where appropriat

e
a. acid a has a pka of 6.0 what is its ka?
b. acid b has a pka of 8.60 whats its ka?
c. acid c has a pka of -2.0 whats its ka?

How do you determine?
Chemistry
1 answer:
Tems11 [23]3 years ago
8 0

Explanation:

Ka is the acid dissociation constant. pKa is simply the -log of this constant.

Mathematically;

pKa = - log Ka

Ka = 10^-pKa

a. acid a has a pka of 6.0 what is its ka?

Ka = 10^-6 = 10⁻⁶

b. acid b has a pka of 8.60 whats its ka?

Ka = 10^-8.6 = 2.51e⁻⁹

c. acid c has a pka of -2.0 whats its ka?

Ka = 10^-(-2) = 10^2 = 100

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Answer:

C. CH3COOH, Ka = 1.8 E-5

Explanation:

analyzing the pKa of the given acids:

∴ pKa = - Log Ka

A. pKa = - Log (1.0 E-3 ) = 3

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C. pKa = - Log (1.8 E-5) = 4.745

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We choose the (C) acid since its pKa close to the expected pH.

⇒ For a buffer solution formed from an acid and its respective salt, we have the equation Henderson-Hausselbach (H-H):

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∴ pKa = 4.745

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⇒ - 0.245 = Log ([CH3COO-]/[CH3COOH])

⇒ 0.5692 = [CH3COO-]/[CH3COOH]

∴ Ka = 1.8 E-5 = ([H3O+].[CH3COO-])/[CH3COOH]

⇒ 1.8 E-5 = [H3O+](0.5692)

⇒ [H3O+] = 3.1623 E-5 M

⇒ pH = - Log ( 3.1623 E-5 ) = 4.5

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