Which element contains four electrons in its third and outer main energy level?
1 answer:
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<u>Answer:</u> The rate of heat flow is 3.038 kW and the rate of lost work is 1.038 kW.
<u>Explanation:</u>
We are given:
Rate of flow of ideal gas , n = 4 kmol/hr = (Conversion factors used: 1 kmol = 1000 mol; 1 hr = 3600 s)
Power produced = 2000 W = 2 kW (Conversion factor: 1 kW = 1000 W)
We know that:
(For isothermal process)
So, by applying first law of thermodynamics:
.......(1)
Now, calculating the work done for isothermal process, we use the equation:
where,
= change in work done
n = number of moles = 1.11 mol/s
R = Gas constant = 8.314 J/mol.K
T = temperature = 475 K
= initial pressure = 100 kPa
= final pressure = 50 kPa
Putting values in above equation, we get:
Calculating the heat flow, we use equation 1, we get:
[ex]\Delta q=3.038kW[/tex]
Now, calculating the rate of lost work, we use the equation:
Hence, the rate of heat flow is 3.038 kW and the rate of lost work is 1.038 kW.
<h3>Answer:</h3>
0.0253 mol H₂O
<h3>General Formulas and Concepts:</h3><u>Math</u>
<u>Pre-Algebra</u>
Order of Operations: BPEMDAS
- Brackets
- Parenthesis
- Exponents
- Multiplication
- Division
- Addition
- Subtraction
- Left to Right<u> </u>
<u>Chemistry</u>
<u>Atomic Structure</u>
- Reading a Periodic Table
<u>Stoichiometry</u>
- Using Dimensional Analysis
<u>Step 1: Define</u>
[Given] 0.456 g H₂O (water)
<u>Step 2: Identify Conversions</u>
[PT] Molar Mass of H - 1.01 g/mol
[PT] Molar Mass of O - 16.00 g/mol
Molar Mass of H₂O - 2(1.01) + 16.00 = 18.02 g/mol
<u>Step 3: Convert</u>
- [DA] Set up:
- [DA] Multiply/Divide [Cancel out units]:
<u>Step 4: Check</u>
<em>Follow sig fig rules and round. We are given 3 sig figs.</em>
0.025305 mol H₂O ≈ 0.0253 mol H₂O