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Alex777 [14]
3 years ago
11

How much is a dogggggggggggggggggg

Chemistry
2 answers:
skelet666 [1.2K]3 years ago
3 0

Answer:

it is 7

Explanation:

dogs are 7 HOPE THIS HELPED kidding i don get the question

snow_lady [41]3 years ago
3 0

Explanation:

DON"T EAT MY DOG OR I"LL EAT YOU

<h2><u><em>You better watch out</em></u></h2><h2><u><em>You better not cry</em></u></h2><h2><u><em>You better not pout</em></u></h2>
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Which physical property can be used to classify oxygen, helium, propane, and hydrogen as being similar?
PSYCHO15rus [73]

Answer:

state of matter

Explanation:

Because there are three state of matter namely:liquid,solid and gas and oxygen is a gas.

4 0
4 years ago
In a solution, when the suspension of one kind of molecules is blended or dissolved with another, the ________ properties are no
Sidana [21]

Answer:

chemical

Explanation:

The chemical properties determine the identity of a substance and are not changed when there is no reaction. In the solution, what takes place is a physical change, which is a change of state (for example, going from solid to aqueous form).

8 0
3 years ago
A solution of carbonic acid is at equilibrium. How would the system change is more carbonic acid was added to the solution
7nadin3 [17]

Answer:

The equilibrium position shifts to the right, in accordance to the constraint principle

3 0
3 years ago
The electronic configuration of an element is given below.
Amiraneli [1.4K]

 The statement  which  is true  about  the reactivity  of  element  with          1S²2S²2P⁶3S¹   is

 it is reactive   because it has to lose one  electron  to have  a full  outermost  energy  level.

<u><em>Explanation</em></u>

  • <u><em> </em></u>Element  with     1S²2S²2P⁶3S¹  electron configuration  is    a sodium  metal.
  •    sodium  has  one  electron  in the outermost energy level.
  • for  sodium to have  a full  outermost  energy level (  8 electrons) it   loses  the  1  electron   in 3S¹ to  form   a positively  charged ion. (Na⁺)
4 0
3 years ago
Titanium and chlorine react to form titanium(IV) chloride, like this:
leva [86]

Answer:

the value of equilibrium constant for the reaction is 8.5 * 10⁷

Explanation:

Ti(s) + 2 Cl₂(g) ⇄ TiCl₄(l)

equilibrium constant Kc = \frac{1}{[Cl_2]^2}

Given that,

We are given:

Equilibrium amount of titanium = 2.93 g

Equilibrium amount of titanium tetrachloride = 2.02 g

Equilibrium amount of chlorine gas = 1.67 g

We calculate the No of mole = mass / molar mass

mass of chlorine gas = 1.67 g

Molar mass of chlorine gas = 71 g/mol

mole of chlorine = 1.67 / 71

= 7.0L

Concentration of chlorine is = no of mole / volume

= 0.024 / 7

= 3.43 * 10⁻³M

equilibrium constant Kc  = \frac{1}{[Cl_2]^2}

= \frac{1}{[3.43 * 10^-^3]^2}

= 8.5 * 10⁷

4 0
4 years ago
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