Ask question

Ask question

All categories

3 years ago

7

In a sale, the price of a computer is reduced by $124. The sale price is $1,394. Find the marked price (original price) and the

rate of the discount. Round the discount rate to the nearest tenth of a percent if necessary

1 answer:

Alika [10]3 years ago

3 0

Easy,

$1394+$124=$1518

This is the original selling price, but $194 was taken off, resulting in $1394.

Now to find Percent Markdown, use this formula:

Percent Markdown= $\frac{Markdown Amount}{Selling Price} *100$

To find Markdown:

Markdown=Original Selling Price-Reduced Price

Now plug in what you have.

Markdown=$1518-$1394=
M=124

As we already knew, the Markdown is 124.

Now,

<span>Percent Markdown= </span> $\frac{124}{1394} *100$
PM=0.088952654*100
PM=8.9 (rounded)

Thus, the percent increase, is 8.9%.

You might be interested in

I need help with my math homework. The questions is: Find all solutions of the equation in the interval [0,2π).

Aleksandr-060686 [28]

Answer:

$\frac{7\pi}{24}$ and $\frac{31\pi}{24}$

Step-by-step explanation:

$\sqrt{3} \tan(x-\frac{\pi}{8})-1=0$

Let's first isolate the trig function.

Add 1 one on both sides:

$\sqrt{3} \tan(x-\frac{\pi}{8})=1$

Divide both sides by $\sqrt{3}$ :

$\tan(x-\frac{\pi}{8})=\frac{1}{\sqrt{3}}$

Now recall $\tan(u)=\frac{\sin(u)}{\cos(u)}$ .

$\frac{1}{\sqrt{3}}=\frac{\frac{1}{2}}{\frac{\sqrt{3}}{2}}$

or

$\frac{1}{\sqrt{3}}=\frac{-\frac{1}{2}}{-\frac{\sqrt{3}}{2}}$

The first ratio I have can be found using $\frac{\pi}{6}$ in the first rotation of the unit circle.

The second ratio I have can be found using $\frac{7\pi}{6}$ you can see this is on the same line as the $\frac{\pi}{6}$ so you could write $\frac{7\pi}{6}$ as $\frac{\pi}{6}+\pi$ .

So this means the following:

$\tan(x-\frac{\pi}{8})=\frac{1}{\sqrt{3}}$

is true when $x-\frac{\pi}{8}=\frac{\pi}{6}+n \pi$

where $n$ is integer.

Integers are the set containing {..,-3,-2,-1,0,1,2,3,...}.

So now we have a linear equation to solve:

$x-\frac{\pi}{8}=\frac{\pi}{6}+n \pi$

Add $\frac{\pi}{8}$ on both sides:

$x=\frac{\pi}{6}+\frac{\pi}{8}+n \pi$

Find common denominator between the first two terms on the right.

That is 24.

$x=\frac{4\pi}{24}+\frac{3\pi}{24}+n \pi$

$x=\frac{7\pi}{24}+n \pi$ (So this is for all the solutions.)

Now I just notice that it said find all the solutions in the interval $[0,2\pi)$ .

So if $\sqrt{3} \tan(x-\frac{\pi}{8})-1=0$ and we let $u=x-\frac{\pi}{8}$ , then solving for $x$ gives us:

$u+\frac{\pi}{8}=x$ ( I just added $\frac{\pi}{8}$ on both sides.)

So recall $0\le x$ .

Then $0 \le u+\frac{\pi}{8}$ .

Subtract $\frac{\pi}{8}$ on both sides:

$-\frac{\pi}{8}\le u$

Simplify:

$-\frac{\pi}{8}\le u$

$-\frac{\pi}{8}\le u$

So we want to find solutions to:

$\tan(u)=\frac{1}{\sqrt{3}}$ with the condition:

$-\frac{\pi}{8}\le u$

That's just at $\frac{\pi}{6}$ and $\frac{7\pi}{6}$

So now adding $\frac{\pi}{8}$ to both gives us the solutions to:

$\tan(x-\frac{\pi}{8})=\frac{1}{\sqrt{3}}$ in the interval:

$0\le x$ .

The solutions we are looking for are:

$\frac{\pi}{6}+\frac{\pi}{8}$ and $\frac{7\pi}{6}+\frac{\pi}{8}$

Let's simplifying:

$(\frac{1}{6}+\frac{1}{8})\pi$ and $(\frac{7}{6}+\frac{1}{8})\pi$

$\frac{7}{24}\pi$ and $\frac{31}{24}\pi$

$\frac{7\pi}{24}$ and $\frac{31\pi}{24}$

5 0

3 years ago

11 3<br>- 50 ml =<br>A 2.41<br>B 2.91<br>C<br>3.351<br>D<br>3.451

julsineya [31]

Es número c por qué esa es la respuesta

5 0

4 years ago

<img src="https://tex.z-dn.net/?f=%5Cfrac%7Bs%7D%7B2%7D" id="TexFormula1" title="\frac{s}{2}" alt="\frac{s}{2}" align="absmiddle

Olegator [25]

S = 92

Explanation: I just know

4 0

3 years ago

Read 2 more answers

The button on Jack's pants has a diameter of 8 millimeters. What is the button's circumference?

aniked [119]

I think the answer is 25.12 millimeters

7 0

3 years ago

How to solve 2m - 3 = 13

Virty [35]

Answer:

m=8

Step-by-step explanation:

8 0

3 years ago

Read 2 more answers