What is the 15th term in the sequence using the given formula?

While on a beach vacation, Tasha makes a scale drawing of points of interest between two

alexdok [17]

Answer:

The distance between the two piers is <u>3 miles.</u>

Step-by-step explanation:

If in Tasha's drawing 2cm represents 0.5 miles between the two piers, and the distance between the two piers in Tasha's drawing is 12cm.

The answer is found by <u>the rule of three: </u>

2 cm : 0.5 miles

12 cm : X

X = (12 * 0.5) / 2

X = 3 miles.

The distance between the two piers is actually 3 miles.

5 0

3 years ago

10% of 360 is how much more than 5% of 360

Fittoniya [83]

Answer:

10% of 360 is 18 more than 5% of 360.

Hope it helps you a follow would be appreciated

4 0

3 years ago

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Aisha can use the expression 120 divided by 10 to determine the solution to which problem?

pentagon [3]

Answer:

What is 10% of 120?

Step-by-step explanation:

120 / 10 = 12

10% of 120 = 12

We have a match.

Let's do the others, just to be sure it's the only one.

10% of 12 = 1.2

25% of 120 = 30

25% of 120 = 3

8 0

3 years ago

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If My−NxN=Q, where Q is a function of x only, then the differential equation M+Ny′=0 has an integrating factor of the form μ(x)=

hammer [34]

Answer with Step-by-step explanation:

We are given that

$(21x^2y+2xy+7y^3)dx+(x^2+y^2)dy=0$

Compare with

$Mdx+Ndy=0$

Then, we get

$M=21x^2y+2xy+7y^3$

$N=x^2+y^2$

Differentiate M w.r.t y

$M_y=21x^2+2x+21y^2$

Differentiate N w.r.t x

$N_x=2x$

$\frac{M_y-N_x}{N}=\frac{21x^2+2x+21y^2-2x}{x^2+y^2}=\frac{21(x^2+y^2)}{x^2+y^2}=21$

Q=21

$I.F=e^{\int 21 dx}=e^{21x}$

$M=e^{21x}(21x^2+2xy+7y^3)$

$N=e^{21x}(x^2+y^20$

Solution is given by

$\int_{y\;constant} Mdx+\int_{x\;free\;terms} Ndy=C$

$\int_{y\;constant} e^{21x}(21x^2y+2xy+7y^3)dx=C$

$\int_{y\;constant}21x^2ye^{21x} dx+\int_{y\;constant}2xye^{21x}dx+\int_{y\;constant}7y^3e^{21x}dx=C$

Using partial integration

$u\cdot v dx=u\int vdx-\int (\frac{du}{dx}\int vdx)dx$

$21x^2y}\frac{e^{21x}}{21}-2y\int xe^{21x}dx+\frac{2xye^{21x}}{21}-\frac{2y}{21}\int e^{21x}dx+\frac{7y^3e^{21x}}{21}=C$

$x^2ye^{21x}-\frac{2xye^{21x}}{21}+\frac{2ye^{21x}}{441}+\frac{2xye^{21x}}{21}-\frac{2ye^{21x}}{441}+\frac{7y^3e^{21x}}{21}=C$

$x^2ye^{21x}+\frac{y^3e^{21x}}{3}=C$

6 0

4 years ago

Solve the equation. -4(3 - 2x) + 2x = 2x - 8 A) x = 2 B) x = -1 C) x = 1/ 2 D) x = 1/ 3

sertanlavr [38]

-4(3-2x)+2x=2x-8
First Distribute your -4 to get -12+8x+2x=2x-8
Then combine like terms to get -12+10x=2x-8
Add 8 over to the -12 to get -4+10x=2x
Subtract 10x from 2x to get -4=-8x
Finally, divide -4 by -8x to get x=1/2.
The correct answer is Letter C.

7 0

3 years ago

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