The time it takes for a ball to complete the trip is given to be 4.10 s. This implies that the trip going up of the ball is equal to 2.05 s. Using this time to determine the initial speed, we have,
Vf = Vo - gt
Vf is the final speed which is equal to 0 on the topmost location of the ball.
0 = Vo - (9.8 m/s²)(2.05 s)
Vo = 20.09 m/s
At 0.5 s,
Vf = 20.09 m/s - (9.8 m/s²)(0.5 s)
Vf = 15.19 m/s
Thus, the speed of the ball when the height is in level with the top of the flagpole is 15.19 m/s.
Some rewards are 2.33 miles in a hour so you have to move in 700 degrees to get the system moving faster soo 700+ 2.33 divide by 3
Answer:
(a) Relative speed of Sam = -7 mph
(b) Relative speed of George = 7 mph
Explanation:
We have given speed of Sam 65 mph in north direction.
And speed of George is 72 mph also in north direction
We have find the relative velocity of both Sam and George
(a) Speed of Sam relative to George = speed of Sam - speed of George = 65 -72 = -7 mph
(b) Speed of George with respect to Sam = speed of George - speed of Sam = 72-65 = 7 mph
Given:
F_gravity = 10 N
F_tension = 25 N
Let's find the net centripetal force exterted on the ball.
Apply the formula:
From the given figure, the force acting towards the circular path will be positive, while the force which points directly away from the center is negative.
Hence, the tensional force is positive while the gravitational force is negative.
Thus, we have:
Therefore, the net centripetal force exterted on the ball is 15 N.
ANSWER:
15 N
The light must be either very dim or else non-existent.
We can't see the light wave or the label.