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ozzi
3 years ago
11

When adding 3 and -9, how do you know that the sun is negative?

Mathematics
1 answer:
siniylev [52]3 years ago
5 0
Since the absolute value of the negative number is greater than the positive number, the sum is negative.

Hope this helps!
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The shape of the distribution of the time required to get an oil change at a 10 minute oil change facility is unknown. However,
lyudmila [28]

Answer:

The answer is below

Step-by-step explanation:

a) For a normal model the sample size has to be equal or greater than 30 so that it can be a normal distribution.

b) Given that:

μ = 11.2 minutes, σ = 4.8 minutes, n = 45

The z score determines how many standard deviations the raw score is above or below the mean. It is given by:

z=\frac{x-\mu}{\sigma} \\For\ a\ sample\ size(n)\\z=\frac{x-\mu}{\sigma/\sqrt{n} }

For x < 10 minutes

z=\frac{x-\mu}{\sigma/\sqrt{n} }\\\\ z=\frac{10-11.2}{4.8/\sqrt{45} }= -1.68

Therefore from the normal distribution table, P(x < 10) = P(z < -1.68) =  0.0465

7 0
3 years ago
Between 0 degrees Celsius and 30 degrees Celsius, the volume V (in cubic centimeters) of 1 kg of water at a temperature T is giv
Ira Lisetskai [31]

Answer:

T = 3.967 C

Step-by-step explanation:

Density = mass / volume

Use the mass = 1kg and volume as the equation given V, we will come up with the following equation

D = 1 / 999.87−0.06426T+0.0085043T^2−0.0000679T^3

   = (999.87−0.06426T+0.0085043T^2−0.0000679T^3)^-1

Find the first derivative of D with respect to temperature T

dD/dT = \dfrac{70000000\left(291T^2-24298T+91800\right)}{\left(679T^3-85043T^2+642600T-9998700000\right)^2}

Let dD/dT = 0 to find the critical value we will get

\dfrac{70000000\left(291T^2-24298T+91800\right)}  = 0

Using formula of quadratic, we get the roots:

T =  79.53 and T = 3.967

Since the temperature is only between 0 and 30, pick T = 3.967

Find 2nd derivative to check whether the equation will have maximum value:

-\dfrac{140000000\left(395178T^4-65993368T^3+3286558821T^2+2886200857800T-121415215620000\right)}{\left(679T^3-85043T^2+642600T-9998700000\right)^3}

Substituting the value with T=3.967,

d2D/dT2 = -1.54 x 10^(-8)    a negative value. Hence It is a maximum value

Substitute T =3.967 into equation V, we get V = 0.001 i.e. the volume when the the density is the highest is at 0.001 m3 with density of

D = 1/0.001 = 1000 kg/m3

Therefore T = 3.967 C

3 0
3 years ago
Robert has 17 lb of grain he would like to put into sacks. Each sack will hold three pounds. How many sacks will he need?
satela [25.4K]

Answer:

6

Step-by-step explanation:

17/3=5.67

since you can't have 0.67 sack. you just round it up to 6

5 0
3 years ago
Read 2 more answers
If p(x)=x3-3x2,then find the value of p(1)
PtichkaEL [24]
-2


Mark brainliest please


Hope this helps you
6 0
2 years ago
Read 2 more answers
Someone help please I’ll appreciate it thank you
DENIUS [597]
Doing the same onee i need help!!


please
3 0
2 years ago
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