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3 years ago

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Volleyball

2 answers:

Jobisdone [24]3 years ago

8 0

Identify key terms : Hand-eye Coordination, physically activity, sportsmanship.

1. The author is informing people about the benefits of regular exercising.

2.Good sportsmanship gives advantages

3.Social Interaction can boost your mood.

4.Quick reactions help you defeat opponents.

5.Sports may be competitive but they teach you valuable life lessons.

tankabanditka [31]3 years ago

6 0

Answer:

1. The author is informing people about the benefits of regular exercising.

2.Good sportsmanship gives advantages

3.Social Interaction can boost your mood.

4.Quick reactions help you defeat opponents.

5.Sports may be competitive but they teach you valuable life lessons.

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What is the mass and weight of a 10kg object on the moon where the force of gravity is 1/6-th that of the earth's?

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<span>Mass on Earth = 10kg
Mass on Moon = 10kg

Weight on Earth=100N
Weight on Moon=100/6 = 16.66 N</span>

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Mention two advantage of writing very big and small numbers in tge power of ten.<br>

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A force is required for any change in an object's motion to occur.<br><br> True<br> False

sertanlavr [38]

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3 years ago

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A baseball is thrown at an angle of 25 degrees relative to the ground at a speed of 23 m/s. If the ball was caught 42 m from the

ExtremeBDS [4]

Answer:

a) $v_{0y} = 9.72 m/s$

b) $v_{0x} = 20.85 m/s$

c) $t = 2.01 s$

d) $h_{max} = 4.82 m$

Explanation:

a) The initial vertical velocity is given by:

$v_{0y} = v*sin(\theta)$

Where:

θ: 25°

v: is the magnitude of the speed = 23 m/s

$v_{0y} = 23 m/s*sin(25) = 9.72 m/s$

b) The initial horizontal velocity can be calculated as follows:

$v_{0x} = v*cos(\theta) = 23 m/s*cos(25) = 20.85 m/s$

c) The flight time can be calculated using the following equation:

$v_{0x} = \frac{x}{t}$

Where:

x: is the total distance = 42 m

$t = \frac{x}{v_{0x}} = \frac{42 m}{20.85 m/s} = 2.01 s$

d) The maximum height is given by:

$v_{fy}^{2} = v_{0y}^{2} - 2gh_{max}$

Where:

$v_{fy}$ : is the final vertical velocity =0 (at the maximum heigth)

g: is the gravity = 9.81 m/s²

$h_{max} = \frac{v_{0y}^{2}}{2g} = \frac{(9.72 m/s)^{2}}{2*9.81 m/s^{2}} = 4.82 m$

I hope it helps you!

7 0

3 years ago