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Levart [38]
3 years ago
9

A force is required for any change in an object's motion to occur. True False

Physics
2 answers:
sertanlavr [38]3 years ago
7 0

Answer:

True

Explanation:

an object in motion stays in motion unless acted upon by another force

Volgvan3 years ago
5 0

Answer/Explanation:

True. A force is what causes a movement in the first place. In order for an object to change motion a different force must be applied such as its opposing force.

<u>Natural force: Thrust</u>

Opposing force is drag.

Other forces are gravity and lift.

The opposing force will reverse the motions direction, the other forces will just change the direction without reversing.

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The "Garbage Project" at the University of Arizona reports that the amount of paper discarded by households per week is normally
Lorico [155]

Answer:

54%

Explanation:

We are given that

S.D=4.2 lb

Mean=\mu=9.4 lb

We have to find the percentage of household throw out at least 9 lb of paper  a week.

Normal distribution formula :

P(X\geq a)=P(z\geq \frac{a-\mu}{\sigma})

We have a=9

P(X\geq 9)=P(z\geq \frac{9-9.4}{4.2})=P(z\geq -0.1)

P(X\geq 9)=1-P(z

P(X\geq 9)=1-0.4602=0.5398\times 100=54%

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lesya692 [45]

The answer is A i just took the test.

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3 years ago
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n isolated charged soap bubble of radius R0=7.45 cmR0=7.45 cm is at a potential of V0=307.0 volts.V0=307.0 volts. If the bubble
Gnesinka [82]

Complete Question

An isolated charged soap bubble of radius R0 = 7.45 cm  is at a potential of V0=307.0 volts. V0=307.0 volts. If the bubble shrinks to a radius that is 19.0%19.0% of the initial radius, by how much does its electrostatic potential energy ????U change? Assume that the charge on the bubble is spread evenly over the surface, and that the total charge on the bubble r

Answer:

The difference is    U_f -U_i = 16 *10^{-7} J

Explanation:

From the question we are told that

     The radius of the soap bubble  is  R_o =  7.45 \ cm =  \frac{7.45}{100} =  0.0745 \ m

      The potential of the soap bubble is  V_1  =307.0 V

      The new radius of the soap bubble  is R_1 =  0.19 * 7.45=1.4155\ cm = 0.014155 \ m

The initial electric potential is mathematically represented as

     U_i  = \frac{V_1^2 R_o }{2k }

The final  electric potential is mathematically represented as

    U_f  = \frac{V_2^2 R_1 }{2k }

The initial potential is mathematically represented as

     V_1 =  \frac{kQ}{R_o}

The final  potential is mathematically represented as

        V_2 =  \frac{kQ}{R_1}

Now  

         \frac{V_2}{V_1}  =  \frac{R_o}{R_1}

substituting values

        \frac{V_2}{V_1}  =  \frac{7.45}{1.4155} =   \frac{1}{0.19}

=>      V_2 =  \frac{V_1}{0.19}

    So

         U_f  = \frac{V_1^2 R_2 }{2k * 0.19^2}

Therefore

        U_f -U_i = \frac{V_1^2 R_2 }{2k * 0.19^2} - \frac{V_1^2 R_o }{2k }

       U_f -U_i =     \frac{V_1^2}{2k} [\frac{ R_1 }{ * 0.19^2} - R_o]

where k is the coulomb's constant with value 9*10^{9} \  kg\cdot m^3\cdot s^{-4}\cdot A^2.

substituting values

       U_f -U_i =     \frac{307^2}{9 * 10^{9}} [\frac{ 0.014155 }{ 0.19^2} - 0.0745]

       U_f -U_i = 16 *10^{-7} J

           

     

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What machine is a seesaw <br><br> mechanical <br><br> compound<br><br> complex <br><br> simple
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I'm pretty sure its simple! I hope this helps
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If an object on a horizontal frictionless surface is attached to a spring, displaced, and then released, it will oscillate. If i
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Explanation:

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