Answer:9A
Explanation:
let the last wire be wire C
According to Kirchhoff's rule
the sum of all currents entering a junction must be equal to the sum of all currents leaving a junction
Ic=Ia+Ib
Ic= 4+5
Ic=9A
Answer:
0.0192A
Explanation:
Since, the reading of the galvanometer is 0 A, the voltage across the resistance R will be:
Step 1
VR = V2
VR = 3.00v
Step 2
Calculating the current through the resistance R as below,
IR = V1 - V2 /R1
IR = 12 - 3 /468
IR =0.0192A
Answer:
Energy is force times distance. For your problem, no matter how long you push, the wall still goes nowhere, so there is no obvious energy transfer. so in conclusion, you actually didn't do anything :(
Explanation:
Answer:
m = 684,865,8 g
Step-by-step explanation
V = 25,365.4 cm^3 Is volume
r = 27g/cm^3 Is density
To calculate mass you use formula:
m= V*r
m = 25,365.4 x 27
m = 684,865,8 g
