Correct question is;
A bag contains 10 counters. 6 of them are white. A counter is taken at random and not replaced. A second counter is taken out of the bag at random. Calculate the probability that only one of the two counters are white
Answer:
probability that only one of the two counters is white = 8/15
Step-by-step explanation:
To solve this question, first of all, let's look at probability we would have to either draw two white counters or two non-white counters (4/10 * 3/9).
Probability(draw 2 white counters) = (6/10 × 5/9) = 30/90 = 1/3
Probability(draw 2 non-white counters) = (4/10 × 3/9) = 2/15
Now, In all other cases, we'll draw exactly one white and one non-white counter, so the odds of this would be;
P(one white counter and one non-white counter) = 1 - [1/3 + 2/15)
= 1 - 7/15 = 8/15
Answer:
(f-g)(x)= (3x + 10) - (5x -3)
f-g = 3x + 10 - 5x + 3
f-g = -2x + 13
Answer:
3.75
Step-by-step explanation:
1.25x3=3.75 easy. you just need to times the height by length
∠1 and ∠2 are equal angles as the lie on same side of transversal, are on parallel lines and are corresponding to each other
thank you
