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Mama L [17]
3 years ago
9

A 12,000 kg railroad car is traveling at 2 m/s when it strikes another 10,000 kg railroad car that is at rest. If the cars lock

together, what is the final speed of the two
Physics
1 answer:
Degger [83]3 years ago
4 0

Answer:

The final speed of the railroad car

V= 1.14 \frac{m}{s}

Explanation:

v_{1}=2.1\frac{m}{s} \\m_{1}=12000kg\\v_{2}=0\frac{m}{s} \\m_{2}=10000kg \\v_{t}=?

m_{1}*v_{1}+m_{2}*v_{2}= (m_{1}+m_{2})*v_{t}\\v_{t}=\frac{m_{1}*v_{1}}{(m_{1}+m_{2})} \\v_{t}=\frac{12000kg*2.1\frac{m}{s} }{(12000+10000)kg} \\v_{t}=1.14 \frac{m}{s}

That's the final speed of the both railroad car

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Explanation:

From the question given above, the following data were obtained:

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