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LenaWriter [7]
1 year ago
12

a box contains 4 yellow, 5 green and 3 blue balls. find the probability of obtaining a yellow ball in a single random draw.

Mathematics
1 answer:
Alex1 year ago
7 0

Notice that the box has a total os 4 + 5 + 3 = 12 balls, since there are 4 that are yellow, then, the probability to randomly obtaining a yellow ball in a single draw is:

P(Yellow)=\frac{\text{ number of yellow balls}}{\text{total number of balls}}=\frac{4}{12}=0.33

therefore, the probability is 0.33 = 33%

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2 years ago
20 points!<br> I need help (asap!!)
EastWind [94]

Answer:

<h2>x = 5</h2><h2>OB = 36</h2><h2>BE = 54</h2>

Step-by-step explanation:

We know that the medians of the triangle divides in a ratio of 2:1. Therefore we have the equation:

\dfrac{9x-9}{2x+8}=\dfrac{2}{1}                <em>cross multiply</em>

1(9x-9)=2(2x+8)             <em>use distributive property a(b + c) = ab + ac</em>

9x-9=(2)(2x)+(2)(8)

9x-9=4x+16                 <em>add 9 to both sides</em>

9x=4x+25                <em>subtract 4x from both sides</em>

5x=25             <em>divide both sides by 5</em>

\boxed{x=5}

OB=9x-9\to OB=9(5)-9=45-9=\boxed{36}

OE=OB:2\to OE=36:2=18\to BE=BO+OE\to BE=36+18=54


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3 years ago
Read 2 more answers
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ella [17]

First of all, expand the left hand side:

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Subtract 3x from both sides:

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So this is the solution. Every number smaller than 8 (excluded) is part of the solution of this inequality.

4 0
2 years ago
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