Rounded to the nearest hundred cubic meters, what is the total capacity (cone and cylinder) of the storage container?
1 answer:
The picture in the attached figure
we know that
the total capacity of the storage container=volume of a cone+volume of cylinder
step 1
find the volume of a cone
volume of a cone=(1/3)*pi*r²*h
r=6 m
h=8 m
so
volume=(1/3)*pi*6²*8-----> 301.44 m³
step 2
find the volume of the cylinder
volume of a cylinder=pi*r²*h
r=6 m
h=10 m
s6
volume=pi*6²*10----> 1130.40 m³
total volume=301.44+1130.4-----> 1431.84 m³-------> 1400 m³
the answer is
1400 m³
we know that
the total capacity of the storage container=volume of a cone+volume of cylinder
step 1
find the volume of a cone
volume of a cone=(1/3)*pi*r²*h
r=6 m
h=8 m
so
volume=(1/3)*pi*6²*8-----> 301.44 m³
step 2
find the volume of the cylinder
volume of a cylinder=pi*r²*h
r=6 m
h=10 m
s6
volume=pi*6²*10----> 1130.40 m³
total volume=301.44+1130.4-----> 1431.84 m³-------> 1400 m³
the answer is
1400 m³
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Answer:
The midpoint of the given coordinates is .
Step-by-step explanation:
We have given two coordinates (3,15) and (20,8).
Let we have given a line segment PQ whose P coordinate is (3,15) and Q coordinate is (20,8).
We have to find out the mid point M(x,y) of the line segment PQ.
Solution,
By the mid point formula of coordinates, which is;
On substituting the given values, we get;
We can also say that
Hence The midpoint of the given coordinates is .