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slamgirl [31]
3 years ago
11

Write an equation for an exponential growth function where the initial population is 74 and the population quadruples during eac

h time period.
Mathematics
1 answer:
Liono4ka [1.6K]3 years ago
6 0
If the population quadruples every period say hour, that means the "rate of growth" is 300%, so whatever the current amount, increased by 3 times as much is 4 times the current amount, or a quadrupled amount.

\bf \qquad \textit{Amount for Exponential Growth}\\\\
A=I(1 + r)^t\qquad 
\begin{cases}
A=\textit{accumulated amount}\\
I=\textit{initial amount}\to &74\\
r=rate\to 300\%\to \frac{300}{100}\to &3.00\\
t=\textit{elapsed time}\\
\end{cases}
\\\\\\
A=74(1+3)^t\implies A=74(4)^t
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Answer:

The answer to your question is vo = 19.62 m/s

Step-by-step explanation:

Data

angle = α = 30°

time = t = 2 s

vo = ?

g = 9.81 m/s²

Formula

                  t = \frac{2vosin\alpha}{g}

Solve for vo

             vo = \frac{tg}{2sin\alpha}

Substitution

            vo = \frac{(2)((9.81)}{2sin 30}

Simplification

           vo = \frac{19.62}{2(0.5)}

           vo = \frac{19.62}{1}

Result

            vo = 19.62 m/s

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