The cinematic equation is:
h (t) = (1/2) * a * t ^ 2 + vo * t + h0
Where,
a: acceleration
vo: initial speed
h0: initial height
Substituting values:
h (t) = (1/2) * (- 32) * t ^ 2 + (0) * t + 9
h (t) = - 16t ^ 2 + 9
For t = 0.2 we have:
h (0.2) = - 16 * (0.2) ^ 2 + 9
h (0.2) = 8.36 feet
To touch the ground we have:
-16t ^ 2 + 9 = 0
16t ^ 2 = 9
t = root (9/16)
t = 0.75 s
Answer:
The height of the cherry after 0.2 seconds is:
h (0.2) = 8.36 feet
the cherry hits the ground at:
t = 0.75 s
I think I know how to do it
Your equation is:
P₁V₁ = P₂V₂
You Know:
Initial:
P₁ = 84 Pa
V₁ = 336 L
New:
P₂ = ?
V₂ = 216L
Plug this into the equation:
P₁V₁ = P₂V₂
(84 Pa)(336 L) = P₂(216 L) Divide 216 on both sides
130.6666666 = P₂
(if your doing significant figures, you have 2 sig figs)
130 Pa = P₂
Answer:
17 1/3
Step-by-step explanation:
the correct answer is 17 1/3
Answer:
Step-by-step explanation:
12
