How does gravity affect objects of the same volume but greater density.

Please help me on this I’ll give 30 points

Rufina [12.5K]

Answer:

1. 10.66 moles of Al

2. 2.5 moles of Al₂O₃

3. 143.87 g of SO₂

Explanation:

The balance chemical equation is as follow,

4 Al + 3 O₂ → 2 Al₂O₃

According to balance chemical equation,

3 moles of O₂ required = 4 moles of Al

So,

8 moles of O₂ will require = X moles of Al

Solving for X,

X = 8 mol × 4 mol / 3 mol

X = 10.66 moles of Al

According to balance chemical equation,

4 moles of Al produced = 2 moles of Al₂O₃

So,

5 moles of Al will produce = X moles of Al₂O₃

Solving for X,

X = 5 mol × 2 mol / 4 mol

X = 2.5 moles of Al₂O₃

The balance chemical equation for the oxidation of carbon disulfide is as follow;

CS₂ + 3 O₂ → CO₂ + 2 SO₂

Step 1: <u>Calculate Moles of CS₂ as;</u>

Moles = Mass / M.Mass

Moles = 85.5 g / 76.14 g/mol

Moles = 1.12 moles of CS₂

Step 2: <u>Find out moles of SO₂ as;</u>

According to balance chemical equation,

1 mole of CS₂ produced = 2 moles of SO₂

So,

1.12 moles of CS₂ will produce = X moles of SO₂

Solving for X,

X = 1.12 mol × 2 mol / 1 mol

X = 2.24 moles of SO₂

Step 3: <u>Calculate Mass of SO₂ as;</u>

Mass = Moles × M.Mass

Mass = 2.24 mol × 64.06 g/mol

Mass = 143.87 g of SO₂

4 0

3 years ago

Sulfur dioxide gas (SO2) and oxygen gas (O2) react to form the liquid product of sulfur trioxide (SO3). How much sulfur dioxide

taurus [48]

1) Balanced chemical equation:

2SO2 (g) + O2 (g) -> 2SO3 (l)

2) Molar ratios

2 mol SO2 : 1 mol O2 : 2 mol SO3

3) Convert 6.00 g O2 to moles

number of moles = mass in grams / molar mass

number of moles = 6.00 g / 32 g/mol = 0.1875 mol O2.

4) Use proportions with the molar ratios

=> 2 moles SO2 / 1 mol O2 = x / 0.1875 mol O2

=> x = 0.1875 mol O2 * 2 mol SO2 / 1 mol O2 = 0.375 mol SO2.

5) Convert 0.375 mol SO2 to grams

mass in grams = number of moles * molar mass

molar mass SO2 = 32 g/mol + 2*16 g/mol = 64 g/mol

=> mass SO2 = 0.375 mol * 64 g / mol = 24.0 g

Answer: 24.0 g of SO2 are needed to react completely with 6.00 g O2.

7 0

3 years ago

The sample concentration was measured at 50mg/ml. The loading concentration needs to be 10mg/ml. The final volume needs to be 25

Svet_ta [14]

Answer:

a) $V_1=5ul$

b) $v=20ul$

Explanation:

From the question we are told that:

initial Concentration $C_1=50mg/ml$

Final Concentration $C_2=10mg/ml$

Final volume needs $V_2 =25ul$

Generally the equation for Volume is mathematically given by

$C_1V_1=C_2V_2$

$V_1=\frac{C_1V_1}{C_2}$

$V_1=\frac{10*25}{50}$

$V_1=5ul$

Therefore

The volume of buffer needed is

$v=V_2-V_1\\\\v=25-5$

$v=20ul$

3 0

3 years ago

Balance the equation (NH4)3 PO4 +NA0H arrow Na3P04 +3NH3 +3H20.

mr_godi [17]

Answer:

Explanation:

(NH4)3 PO4 +NaOH arrow Na3PO4 +3NH3 +3H2O

Start by seeing what happens with the Na. You need 3 on the left, so put a 3 in front of NaOH

(NH4)3 PO4 +3NaOH arrow Na3PO4 +3NH3 +3H2O Next work with the nitrogens. YOu have 3 on the left and 3 on the right, so they are OK. Next Go to the stray oxygens.

You have 3 on left in (NaOH) and three on the right in 3H2O so they are fine as well. The last thing you should look at are hydrogens.

There are 12 + 3 on the left which is 15. There are 9 (in 3NH3) and 6 more in the water. They seem fine.

Why didn't I do something with the PO4^(-3)? The reason is a deliberately stayed away from them and balanced everything else. Since they were untouched with 1 on the left and 1 on the right, they are balanced.

Species Na H O N PO4

Left 3 15 3 3 1

Right 3 15 3 3 1

8 0

3 years ago

Read 2 more answers

hi, 100 points, , will also mark brainly-ist (what's the boiling point of water) ((you don't need to answer that))

BaLLatris [955]

Answer:

212 degrees F, and 100 degrees C.

Explanation:

If the temperature is held constant (which requires some heat input, since evaporation cools things) the liquid will all evaporate. If the temperature is much above 212 F, the water will boil. That means that it wont just evaporate from the surface but will form vapor bubbles, which then grow, inside the liquid itself. :)

6 0

3 years ago