Answer:
Melting: the substance changes back from the solid to the liquid. Condensation: the substance changes from a gas to a liquid. Vaporization: the substance changes from a liquid to a gas. Sublimation: the substance changes directly from a solid to a gas without going through the liquid phase.
Explanation:
Chromatography is used in purification. Drugs analysts may use the technique to separate the active molecule in a drug molecule, for efficacy or toxicity analysis, from the other drug components.
Explanation:
Chromatography is used to separate a mixture of different components based on the size of their molecules. In liquid chromatography, the mixture is dissolved in a solvent that acts as the mobile phase and then passed along a stationary phase with different kinds of pores, As the mixture passes through the pores, their different components are separated because they take different times to pass through the stationary phase because of their different rates in passing through the pores.
In gas chromatography, a gas is used as a mobile phase while a liquid is used as the stationary phase.
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Answer:can u anser my question
Explanation: On page 17, author Joey Bartolomeo writes “Caleb participated in the investigation by testifying about what happened during the health seminar at his school.” As it is used in that sentence, what does "testify" mean? *
0 points
C. to persuade someone to join a group
B. to disguise or hide from sight
A. to argue so as to make a person agree
D. to talk and answer questions about something after formally promising to tell the truth
Answer is: The solution has now become a good conductor of electricity.
Hydrochloric acid (HCl) dissociate on positive ions or cations of hydogen (H⁺) and negative ions or anions of chlorine (Cl⁻) accordinf to balanced chemical reaction:
HCl(aq) → H⁺(aq) + Cl⁻(aq).
When there are free cations and ions, water solution can conduct electricity.
Answer:
116.3 grCO2
Explanation:
1st - we balance the equation so that it finds the same amount of elements of the product side and of the reagent side
C6H6 +15/2 O2⟶ 6CO2 +3 H2O
2nd - we calculate the limiting reagent
39.2gr C6H6*(240grO2/78grC6H6)=120 grO2
we don't have that amount of oxygen so this is the excess reagent and oxygen the limiting reagent
3rd - we use the limiting reagent to calculate the amount of CO2 in grams
105.7grO2*(264grCO2/240grO2)=116.3 grCO2