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andrey2020 [161]
3 years ago
12

Hydrogenation reactions, in which H2 and an "unsaturated" organic compound combine, are used in the food, fuel, and polymer indu

stries. In the simplest case, ethene (C2H4) and H2 form ethane (C2H6). If 127 kJ is given off per mole of C2H4 reacting, how much heat (in kJ) is released when 10.1 kg of C2H6 forms? Enter a positive number since released implies a negative number. Enter to 0 decimal places.
Chemistry
1 answer:
gayaneshka [121]3 years ago
3 0

Answer:

42672 kJ

Explanation:

Chemical reaction:

C₂H₄ + H₂ → C₂H₆ + heat

Now we calculate the number of moles of ethane C₂H₆:

number of moles = mass / molecular weight

number of moles of ethane = 10.1 / 30 = 0.336 kmoles = 336 moles

And determine the heat released:

if      127 kJ are released when 1 mole of C₂H₆ is produced

then X kJ are released when 336 moles of C₂H₆ is produced

X = (127 × 336) / 1 = 42672 kJ

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6 0
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Read 2 more answers
Ethylenediamine (en) forms an octahedral complex with Ni2+(aq) with the formula [Ni(en)3]2+. Ni2+(aq) + 3 en ⇌ [Ni(en)3]2+(aq) K
yawa3891 [41]

Answer:

3.125\times 10^{-19} mol/L is the concentration of Ni^{2+}(aq) in the solution.

Explanation:

Ni^{2+}(aq) + 3 en\rightleftharpoons [Ni(en)_3]^{2+}(aq)

Concentration of nickel ion = [Ni^{2+}]=x

Concentration of nickel complex= [[Ni(en)_3]^{2+}]=\frac{0.16 mol}{2 L}=0.08 mol/L

Concentration of ethylenediamine = [en]=\frac{0.80 mol}{2 L}=0.40 mol/L

The formation constant of the complex = K_f=4.0\times 10^{18}

The expression of formation constant is given as:

K_f=\frac{[[Ni(en)_3]^{2+}]}{[Ni^{2+}][en]^3}

4.0\times 10^{18}=\frac{0.08 mol/L}{x\times (0.40 mol/L)^3}

x=\frac{0.08 mol/L}{4.0\times 10^{18}\times (0.40 mol/L)^3}

x=3.125\times 10^{-19} mol/L

3.125\times 10^{-19} mol/L is the concentration of Ni^{2+}(aq) in the solution.

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