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3 years ago

Please Need help asap

Chemistry

1 answer:

ruslelena [56]3 years ago

4 0

Answer:

Explanation:

The number of protons and neutrons of an element is the same. the electrons are the only thing that can differ. The atomic number equal the protons and neutrons.

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A tornado is formed by _____.

liberstina [14]

Answer:

wind..........................

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3 years ago

Students mixed 20 mL of white glue and 20 mL of water in a cup. They added three drops of food coloring to the mixture. Then, 15

Dmitry_Shevchenko [17]

Hi im here to help!

Answer: a chemical reaction occurred because a new substance was formed with new properties!

Explanation: when u mix glue water and borax it forms into a new substance which is a chemical reaction

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3 years ago

Name the following ionic compounds involving ionic bonds

goblinko [34]

ionic compounds usually involve a metal and a non metal, and non ionic (or covalent) bonds are usually between 2 non metals
a) Fe3P2 Iron is a metal, Phosphorus is a non metal so it is likely to be non ionic

p.s metals are on the left of the periodic table and non metals on the right

3 0

3 years ago

A 18.08-g sample of the ionic compound , where is the anion of a weak acid, was dissolved in enough water to make 116.0 mL of so

Oksi-84 [34.3K]

Answer:

a) 129.14 g/mol

b) 8.87

Explanation:

Given that:

mass of the ionic compound [NaA] = 18.08 g

Volume of water = 116.0 mL = 0.116 L

Let the mole of the acid HCl = 0.140 M

Volume of the acid = 500.0 mL = 0.500 L

pH = 4.63

$V_{equivalence}_{acid}$ = 1.00 L

Equation for the reaction can be represented as:

$NaA_{(aq)} + HCl_{(aq)} -----> HA_{(aq)} + NaCl_{(aq)$

From above; 1 mole of an ionic compound reacts with 1 mole of an acid to reach equivalence point = 0.140 M × 1.00 L

= 0.140 mol

Thus, 0.140 mol of HCl neutralize 0.140 mol of ionic compound at equilibrium

Thus, the molar mass of the sample = $\frac{18.08g}{0.140 mole}$

= 129.14 g/mol

b) since pH = pKa

Then pKa of HA = 4.63

Ka = $10^{-4.63]$

= $2.3*10^{-5}$

$[A^-]equ = \frac{0.140M*1.00L}{1.00L+0.116L}$

$= \frac{0.140 mol}{1.116 L}$

= 0.1255 M

$K_a$ of HA = $2.3*10^{-5}$

$K_b = \frac{1.0*10^{-14}}{2.3*10^{-5}}$

$= 4.35*10^{-10}$

$A_{(aq)}$ + $H_2O_{(l)}$ $\rightleftharpoons$ $HA_{(aq)}$ + $OH^-_{(aq)}$

Initial 0.1255 0 0

Change - x + x + x

Equilibrium 0.1255 - x x x

$K_b = \frac{[HA][OH^-]}{[A^-]}$

$4.35*10^{-10} = \frac{[x][x]}{[0.1255-x]}$

As $K_b$ is very small, (o.1255 - x) = 0.1255

$x = \sqrt{0.1255*4.35*10^{-10}}$

[OH⁻] = $x = 7.4 *10^{-6}$

But pOH = - log [OH⁻]

= - log [ $7.4*10^{-6}$ ]

= 5.13

pH = 14.00 = 5.13

pH = 8.87

6 0

3 years ago

Energy from the Sun is called

WINSTONCH [101]

Energy from the Sun is called Solar Energy! The terms "solar energy" and "solar radiation" simply refer to energy from the sun... So either one would work!

I hope this helped! :)

8 0

4 years ago

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