Question

What is the completely factored form of x^4y-4x^2y-5y

Answer 1

Answer:

$y(x^2+1)(x^2-5)$

Step-by-step explanation:

Factor the expression by first finding a GCF. Each term has the y variable and this can be pulled out as the GCF.

$x^4y-4x^2y-5y\\y(x^4-4x^2-5)$

To further factor the expression break the polynomial into two binomials.

To factor into two binomials, find factors that multiply to -5 and add to -4.

-5 and 1 are factors and these make the binomials $(x^2+1)(x^2-5)$.

The final factorization is $y(x^2+1)(x^2-5)$