The point of the experiment has been foiled by the choice to hand water one group and use sprinklers on the other. Whether talking to the plant or not did anything can't be proven because of this. If the student were to try to publish this experiment and the outcomes. Critics would be able to use the unequal treatment in water supply as a reason to discredit his/her experiment and dismiss the claims. When performing an experiment like this it is very important to treat each side as equal as possible.
Answer:
Explanation:
<em>Let the ability to break down the red color in beets be represented by the allele </em><em>B</em><em>. The inability would be represented by the allele </em><em>b</em><em>.</em>
A nonsecretor's genotype would be BB or Bb while a secretor's genotype would be bb.
A nonsecretor woman with a secretor father would be a carrier with genotype Bb. A nonsecretor man who in a previous marriage had a secretor daughter would also be a carrier with genotype Bb. If the two marries:
<em>Bb x Bb</em>
<em> BB 2Bb bb</em>
1.
(a) probability of their first child will be a secretor girl = probability of having a girl and being a secretor.
Probability of having a girl = 1/2
Probability of being a secretor = 1/4
<em>probability of their first child will be a secretor girl</em> = 1/2 x 1/4 = 1/8
(b) Probability of their first child being a nonsecretor girl = probability of having a girl and being a nonsecretor.
Probability of having a girl = 1/2
Probability of being a nonsecretor = 3/4
<em>Probability of their first child being a nonsecretor girl = probability of having a girl and being a nonsecretor</em> = 1/2 x 3/4 = 3/8
2. <em>Probability that their first two children will be nonsecretors of either sex = probability of their first being a nonsecretor and of either sex and probability of their second being a nonsecretor and of either sex.</em>
= 3/4 x 3/4 = 9/16
Gonna need a bit more information then that if you want an answer.
