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erastova [34]
3 years ago
6

Based on the tax brackets, what’s the estimated total tax due for a single taxpayer with a taxable income of $43,500?

Mathematics
1 answer:
inysia [295]3 years ago
6 0

Answer:

C. $5,509.50

Step-by-step explanation:

The computation of the estimated total tax due in case of taxable income for $43,500 is shown below:

Since in the question the income brackets and based on the income the different tax is to be charged

For $9,525, the 10% tax is charged i.e

= \$9,525 \times 10\%

= $952.50

Upto $38,700, the 12% tax is charged i.e

= (\$38,700 - \$9,526) \times 12\%

= $3,500.88

The remaining amount left is

= (\$43,500 - \$38,701) \times 22\%

= $1,055.78

Now the total tax due is

= $952.50 + $3,500.88 + $1,055.78

= $5,509.16 approx i.e $5,509.50

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<h3><u>L</u><u>H</u><u>S</u><u>:</u><u>-</u></h3>

\\ \sf\longmapsto 1+tan^2A

\boxed{\sf tanA=\dfrac{sinA}{cosA}}

\\ \sf\longmapsto 1+\dfrac{sin^2A}{cos^2A}

\\ \sf\longmapsto \dfrac{cos^2A+sin^2A}{cos^2A}

\boxed{\sf cos^2A+sin^2A=1}

\\ \sf\longmapsto \dfrac{1}{cos^2A}

\\ \sf\longmapsto \dfrac{1}{1-sin^2A}

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Hence verified

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3 years ago
Simplify 4x^5 X 6x^10
sattari [20]
Use photo math it’s really helpful
6 0
3 years ago
Use the normal distribution of SAT critical reading scores for which the mean is 507 and the standard deviation is 109. Assume t
makvit [3.9K]

Answer:

Step-by-step explanation:

Let X be the variable representing SAT critical reading scores for which the mean is 507 and std dev is 109

X is normal

Critical score for 95% is Z critical = ±1.96

Convert Z to x score as

z=507+1.96(109) and z = 507-1.96(109)

Critical values of X lie in the range

(293.36,720.64)

5 0
3 years ago
Find the vertical and horizontal asymptote if they exist
tresset_1 [31]

Hello!

Vertical asymptotes are determined by setting the denominator of a rational function to zero and then by solving for x.

Horizontal asymptotes are determined by:

1. If the degree of the numerator < degree of denominator, then the line, y = 0 is the horizontal asymptote.

2. If the degree of the numerator = degree of denominator, then y = leading coefficient of numerator / leading coefficient of denominator is the horizontal asymptote.

3. If degree of numerator > degree of denominator, then there is an oblique asymptote, but no horizontal asymptote.

To find the vertical asymptote:

2x² - 10 = 0

2(x² - 5) = 0

(x - √5)(x + √5) = 0

x = √5 and x = -√5

Graphing the equation, we realize that x = -√5 is not a vertical asymptote, so therefore, the only vertical asymptote is x = √5.

To find the horizontal asymptote:

If the degree of the numerator < degree of denominator, then the line, y = 0 is the horizontal asymptote.

Therefore, the horizontal asymptote of this function is y = 0.

Short answer: Vertical asymptote: x = √5 and horizontal asymptote: y = 0

7 0
3 years ago
Is it true that since sin^2x + cos^2x = 1, then sin(x) + cos(x) = 1? Explain your answer.
slava [35]

Answer:

No it is not true because plugging in something like x = pi/4 radians (equivalent to 45 degrees) leads to the left side not being equal to 1. The left side will simplify to sqrt(2). So the equation is not true when x = pi/4 radians. There are infinitely other counter examples to use

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3 years ago
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