Large amounts of water do have a big impact on the weather: indeed, it takes less energy to warm/cool land than water.
Therefore, places near large amounts of water tend to have smaller differences in temperature between summer and winter than places far from waters.
Hence, during winter in Puerto Rico, alongside the coast, the temperature will be higher than in the innermost parts of the island.
Answer:
There will be a phase change at the first interface and no phase change at the second interface:
If the film is 1/4 wavelength thick this restriction will hold
The wavelength of the light in oil is 545 nm / 1.45 = 376 nm
376 nm / 4 = 94 nm
"D" is correct
Answer:
The mass of 0.02 m³ of gold is 386 kilograms
Explanation:
Given:
The density of the gold = 19300 kg/m³.
The volume of gold = 0.02 m³
To Find:
The mass of gold = ?
Solution:
We know that density is mass divided per unit volume.
Thus mathematically
Density = \frac{mass}{volume}Density=
volume
mass
Rewriting in terms of mass ,
Mass = density * volume
On substituting the known values
Mass = 19300 kg/m³ * 0.02 m³
Mass = 386 kilograms
Learn more about Mass and Density:
Mass=?,volume=190,density=4
Mass 350 kg volume 175 density ans
This is not my answer I copied it but hope it helps:)
Computer simulation is useful because it helps in the prediction of what will likely happen in the future using data from past events.
<h3>What is computer simulation?</h3>
- This is the use of computer models to represents a hypothetical scenarios that are likely to be obtained in the real world.
Computer simulations are useful in studying phenomena in the universe because they help us to achieve the followings;
- It helps in the prediction of what will likely happen in the future using data from past events.
- It saves cost and time of carrying out actual experiments.
- It can help prevent a disaster that may occur in the future.
Learn more about computer simulations here: brainly.com/question/22214039
Missing question: "What is the spring's constant?"
Solution:
The object of mass m=6.89 kg exerts a force on the spring equal to its weight:
When the object is attached to the spring, the displacement of the spring with respect to its equilibrium position is
And by using Hook's law, we can find the constant of the spring:
