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natka813 [3]
3 years ago
13

How much kinetic energy a spring that streches 4m would be?

Physics
1 answer:
miv72 [106K]3 years ago
8 0

Answer:

Explanation:bjbhfcvvjkkknbnnnm

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If a driver is tired, the thinking distance will be less. True or false.why?
Evgesh-ka [11]

Answer:

False

Explanation:

When a driver is impaired the brain will need an extra second or two to wake up, after it does wake up it tends to drift off regularly.

8 0
4 years ago
You travel and average speed of 20 km/h in a straight line to get to your grandmothers house. It takes you three hours to get to
Gekata [30.6K]

20\,\dfrac{\mathrm{km}}{\mathrm h}=\dfrac x{3\,\mathrm h}\implies x=60\,\mathrm{km}

5 0
4 years ago
A kayaker needs to paddle north across a 100-m-wide harbor. The tide is going out, creating a tidal current that flows to the ea
Savatey [412]

Answer:

41.81^{\circ}

Explanation:

The tidal current flows to the east at 2.0 m/s and the speed of the kayaker is 3.0 m/s.

Let Vector \overrightarrow{OA} is the tidal current velocity as shown in the diagram.

In order to travel straight across the harbor, the vector addition of both the velocities (i.e the resultant velocity, \vec {R} must be in the north direction.

Let \overrightarrow{AB} is the speed of the kayaker having angle \theta measured north of east as shown in the figure.

For the resultant velocity in the north direction, the tail of the vector \overrightarrow {OA} and head of the vector \overrightarrow{AB} must lie on the north-south line.

Now, for this condition, from the triangle OAB

|\overrightarrow{AB}|\sin \theta=|\overrightarrow{OA}|

\Rightarrow \sin\theta=\frac{|\overrightarrow{OA}|}{|\overrightarrow{AB}|}=\frac 2 3

\Rightarrow \theta=\sin^{-1}\frac23

\Rightarrow \theta=41.81^{\circ}

Hence, the kayaker must paddle in the direction of 41.81^{\circ}  in the north of east direction.

3 0
4 years ago
it is possible to tell if objects in space are moving closer to us or farther away based on which of the following?
valkas [14]
I think you forgot to give the options along with the question. I am answering the question based on my knowledge and research. It is <span>possible to tell if objects in space are moving closer to us or farther away based on several procedures like parallax and standard candles. I hope the answer has come to your help.</span>
7 0
4 years ago
Read 2 more answers
Sebuah benda berjarak 8 cm di depan cermin cekung yang memiliki fokus 12 cm. perbesaran bayangan yang dihasilkan adalah??
Len [333]
1/s' = 1/f - 1/s
        = 1/12 - 1/8
        = 2/24 - 3/24
        = 2-3/24
        = - 1/24
s'= -24
M= |s'/s|
M = |24/8|
M = 3
4 0
3 years ago
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