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bearhunter [10]
3 years ago
7

3. 500ml of 60oC water at is added to a beaker. Water’s specific heat is 4.186 J/g °C. You have 40ml of and unknown substance th

at you add to the same beaker. The unknown substance’s specific heat is 14.3/goC The final temperature of the beaker is 45oC. What was the initial temperature of the unknown substance?
Physics
1 answer:
castortr0y [4]3 years ago
8 0
Idkd djdjdbd djkdmdkdmkrkr r r r. R r
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nan moved 18m to the right and then another 22m to the right if the motion takes 20 seconds what is nans velocity
IrinaVladis [17]
Step 1: list known info

distance(change in position (Δx))= 18m+22m= 40m
time= 20 seconds

Step 2 :solve for velocity

velocity= Δx÷time
v= 40/20= 2m/s

Answer: the velocity is 2 meters per a second (m/s)


7 0
3 years ago
When two license plates are issued they need to be attached to the _________ of the vehicle they were issued for.
Sergio039 [100]

Answer:

Front and the rear bumpers.

Explanation:

When two license plates are issued they need to be attached to the Front and the rear bumpers of the vehicle they were issued for.

7 0
3 years ago
A man performed 500 j of work moving a couch in his living room
Sergio039 [100]

Incomplete question. Missing part:

"it took him 10 seconds to move the couch. What was his power?"

Answer:

50 W

Explanation:

The power developed is given by:

P=\frac{W}{t}

where

W is the work done

t is the time taken

In this problem,

W = 500 J

t = 10.0 s

Substituting into the equation, we find

P=\frac{500}{10}=50 W

6 0
3 years ago
A 1.1-kg uniform bar of metal is 0.40 m long and has a diameter of 2.0 cm. When someone bangs one end of this bar, a 1.5 MHz sho
lyudmila [28]

Answer:

\lambda = 2.22\times 10^{-3}\ m

Explanation:

Given,

mass of the bar = 1.1 Kg

length of rod, l = 0.40 m

diameter of the rod, d = 2 cm

frequency, f = 1.5 MHz

time, t = 0.12 ms

wavelength of the shock wave = ?

Speed of the wave =\dfrac{L}{t}=\dfrac{0.40}{0.12\times 10^{-3}}

   v = 3333.33 m/s

wavelength of the wave

\lambda = \dfrac{v}{f}= \dfrac{3333.33}{1.5\times 10^6}

\lambda = 2.22\times 10^{-3}\ m

6 0
3 years ago
the minimum flying speee for a bird called a house martin is 9.0ms^-1. it reaches this speed by falling from its nest before swo
Lilit [14]

Answer:

The nest must be about  4.15 meters above ground

Explanation:

Use the velocity equation under accelerated motion (acceleration of gravity ):

v_f=v_i+a\,*\,t

which for this case has initial velocity = 0 (falls from the nest), final velocity = 9 m/s, and a = 9.8 m/s^2, then we can find the time needed in air while falling to reach the required speed:

v_f=v_i+a\,*\,t\\9=0+9.8\,t\\t=\frac{9}{9.8} \, sec\\t \approx 0.92\,\, sec

We now use this time value to find the distance covered in free fall during 0.92 seconds:

d=\frac{1}{2} \,9.8 \,t^2=4.9\,(0.92)^2=4.147 \,meters\approx 4.15\,meters

8 0
3 years ago
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