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NemiM [27]
2 years ago
9

A.45 B.30 C.90 D.180 E.40 F.55 G.130 H.50

Mathematics
1 answer:
brilliants [131]2 years ago
4 0

Answer:

m<4=40

Step-by-step explanation:

Supplementary angles form 180 degrees

m<3 is vertical to the 50 degree angle which is equal.

so. m<3=50

m<5=90

90+50=140

180-140=40

m<4=40

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In ΔABC (m∠C = 90°), the points D and E are the points where the angle bisectors of ∠A and ∠B intersect respectively sides BC an
Airida [17]

This is a little long, but it gets you there.

  1. ΔEBH ≅ ΔEBC . . . . HA theorem
  2. EH ≅ EC . . . . . . . . . CPCTC
  3. ∠ECH ≅ ∠EHC . . . base angles of isosceles ΔEHC
  4. ΔAHE ~ ΔDGB ~ ΔACB . . . . AA similarity
  5. ∠AEH ≅ ∠ABC . . . corresponding angles of similar triangle
  6. ∠AEH = ∠ECH + ∠EHC = 2∠ECH . . . external angle is equal to the sum of opposite internal angles (of ΔECH)
  7. ΔDAC ≅ ΔDAG . . . HA theorem
  8. DC ≅ DG . . . . . . . . . CPCTC
  9. ∠DCG ≅ ∠DGC . . . base angles of isosceles ΔDGC
  10. ∠BDG ≅ ∠BAC . . . .corresponding angles of similar triangles
  11. ∠BDG = ∠DCG + ∠DGC = 2∠DCG . . . external angle is equal to the sum of opposite internal angles (of ΔDCG)
  12. ∠BAC + ∠ACB + ∠ABC = 180° . . . . sum of angles of a triangle
  13. (∠BAC)/2 + (∠ACB)/2 + (∠ABC)/2 = 90° . . . . division property of equality (divide equation of 12 by 2)
  14. ∠DCG + 45° + ∠ECH = 90° . . . . substitute (∠BAC)/2 = (∠BDG)/2 = ∠DCG (from 10 and 11); substitute (∠ABC)/2 = (∠AEH)/2 = ∠ECH (from 5 and 6)
  15. This equation represents the sum of angles at point C: ∠DCG + ∠HCG + ∠ECH = 90°, ∴ ∠HCG = 45° . . . . subtraction property of equality, transitive property of equality. (Subtract ∠DCG+∠ECH from both equations (14 and 15).)
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You read 105 pages of a novel over 7 days what is the mean number of pages you read each day
Zolol [24]
105/7=15 
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Hello!? what's 3 + 3
rjkz [21]

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Step-by-step explanation

4 0
2 years ago
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Work out: 0.03 x 0.6
STatiana [176]

0.03 x 0.6

= (3 x 6) / 1000

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4 0
3 years ago
Adonis created a rectangular play area for his dog in his backyard. The length of the long side was 10ft and the length of the s
Drupady [299]

Answer:

The perimeter of the dog's play area is 30 ft

Step-by-step explanation:

Rectangle:

  • The opposite sides are congruent.
  • The opposite angles are congruent.
  • The sum of all four angles of a rectangle is 360°.
  • The sum of two adjacent angles of a rectangle is 180°.
  • The diagonals bisect each other.
  • The perimeter of a rectangle is = 2(Length+width)
  • The area of a rectangle is = Length × width

Given that,

The length of the long side of the dog's play area was = 10 ft.

So, Length of dog's play area is = 10 ft.

The length of the short side of the dog's play area was = 5 ft.

So, width of dog's play area is = 5 ft.

It is a rectangular plot.

So, the perimeter of the dog's play area is =2(Length+width)

                                                                      =2(10+5) ft

                                                                      =2(15) ft

                                                                      =30 ft

5 0
3 years ago
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