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3 years ago

Where in the atmosphere do storms occur?

Physics

2 answers:

mina [271]3 years ago

7 0

Troposphere and Stratosphere

The storms occur in the lowest layer of the atmosphere

Goshia [24]3 years ago

6 0

The answer is troposphere, the layer where a lot of storms occur

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A ball is projected at an immovable wall with a speed vi and bounces back the wall in such a manner that it only has 1/3 of its

sergey [27]

The fraction of the kinetic energy of the ball lost during the collision is $\frac{1}{3}$ .

The given parameters;

initial speed of the ball, = vi
final momentum of the ball, Pf = ¹/₃Pi

The initial and final momentum of the ball is calculated as;

$P_i = m_ivi$

$P_f = m_fv_f = \frac{1}{3} m_iv_i$

The initial and final kinetic energy of the ball is calculated as;

$K.E_i = \frac{1}{2} m_iv_i^2 = \frac{1}{2} P_iv_i\\\\K.E_f = \frac{1}{2} m_fv_f^2= \frac{1}{2} (\frac{1}{3} P_iv_i)= \frac{1}{6} P_iv_i$

The change in the kinetic energy is calculated as;

$\Delta K.E = K.E_f - K.E_i \\\\\Delta K.E = \frac{1}{6} P_iv_i - \frac{1}{2} P_iv_i = \frac{1}{3} P_iv_i$

Thus, the fraction of the kinetic energy of the ball lost during the collision is $\frac{1}{3}$ .

Learn more here:brainly.com/question/18566218

5 0

3 years ago

Which term describes the wave phenomenon in the image?

VashaNatasha [74]

Answer:

wave changes its path from its initial direction so this phenomenon is known as Refraction of wave

Explanation:

When wave travels from one medium to other medium the due to change in the speed of the wave propagation it deviates from its initial path.

The deviation of the wave from its initial path is known as refraction of wave

Here we can see that wave incident on medium 1 with some angle with the boundary

Then it enters into other medium and then travels in other direction

So here wave changes its path from its initial direction so this phenomenon is known as Refraction of wave

8 0

3 years ago

Read 2 more answers

If you were standing on the moon and you had a radio signal transmitter, you could send the radio signal to Earth in 1.28 second

Hatshy [7]

Answer:

Distance between moon and earth = $3.84*10^{5}km$

Explanation:

Distance traveled by radio waves = Velocity of radio waves * Time taken by radio waves

Velocity of radio waves = $3*10^{8}m/s$

Time taken by radio waves = 1.28 seconds

So distance traveled by radio wave = $3*10^{8}*1.28=3.84*10^{8}m$

Distance between moon and earth = $3.84*10^{8}m$ = $3.84*10^{5}km$

7 0

3 years ago

On which one of the surfaces listed below will a toy car released with the same initial speed travel the farthest? *

irinina [24]

Are you gonna list the surfaces or nah

5 0

3 years ago

a hockey player of mass 82 kg is traveling north with a velocity of 4.1 meters per second he collides with the 76 kg player trav

ratelena [41]

mass of first player = 82 kg

speed of first player = 4.1 m/s (towards North)

mass of second player = 76 kg

speed of second player = 3.4 m/s (towards East)

now the two players will collide and stick together so here since there is no external force on the system of two players so we will say momentum of system of players will remain conserved

So here we will have

$P_{1i} = 82 (4.1 \hat j)$

$P_{2i} = 76 (3.4 \hat i)$

now after collision they both move together with same speed so we will have

$P_{1i} + P_{2i} = (m_1 + m_2)v$

$336.2\hat j + 258.4\hat i = (82 + 76)v$

$v = 1.64\hat i + 2.13 \hat j$

so the magnitude of the velocity after they collide is given as

$v = \sqrt{1.64^2 + 2.13^2}$

$v = 2.69 m/s$

direction of motion is given as

$tan\theta = \frac{2.13}{1.64} = 1.3$

$\theta = 52.4 degree$

so they both will move 52.4 degree North of East after collision

7 0

3 years ago