Firstly, we have to convert the 3.20cm/s to m/s which is done by dividing the 3.20 by 100. the answer gives 0.032m/s. Then using the formular v=c/n where v is the apparent speed, c = speed of object and n is the refractive index of medium.we can now solve using the above formular which is 0.032m/s/1.333 = 0.024m/s
A) Acceleration= (282m/s-0m/s)/5.0s= 56.4m/s^2 b) Deceleration=(0m/s-282m/s)/1.40s=201.4m/s^2 (here we reject negative because deceleration already take into account negative) c) for the first one the multiple will be 5.76g for the second one it will be 20.6g
