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bogdanovich [222]
3 years ago
8

If you were standing on the moon and you had a radio signal transmitter, you could send the radio signal to Earth in 1.28 second

s. If radio waves travel at 3.00 X 1018 m/s, what is the distance from the moon to the earth in kilometers?
Physics
1 answer:
Hatshy [7]3 years ago
7 0

Answer:

Distance between moon and earth = 3.84*10^{5}km

Explanation:

 Distance traveled by radio waves = Velocity of radio waves * Time taken by radio waves

 Velocity of radio waves = 3*10^{8}m/s

 Time taken by radio waves = 1.28 seconds

 So distance traveled by radio wave = 3*10^{8}*1.28=3.84*10^{8}m

 Distance between moon and earth = 3.84*10^{8}m=3.84*10^{5}km

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Plz help me solve them! I have final exam on physics tomorrow!!
Katyanochek1 [597]
Acc = (final velocity-initial velocity) / time
acc = ( 22.2m/s - 11.1 m/s) / 2secs
acc = (11.1) / 2
acc = 5.55ms-2

5 0
3 years ago
A train travels 4,000,000 m from New York to Los Angeles and takes about 42 hours to make the entire trip. What is its speed in
barxatty [35]

Answer:

195,714,000 meters per second

I hope this helps!

5 0
3 years ago
What is the force exerted on a moving charge of –2.0 μC at a 20° angle through a magnetic field of 3.0 × 10–4 T with a velocity
egoroff_w [7]

Answer:

The force exerted on a moving charge is 1.02\times 10^{-3}\ N.                

Explanation:

We have,

Charge, q=-2\ \mu C

Magnetic field, B=3\times 10^{-4}\ T

Velocity of charged particle, v=5\times 10^6\ m/s

Angle through the magnetic field, \theta=20^{\circ}

It is required to find the force exerted on a moving charge. Due to the motion in charge, magnetic force acts on it. It can be given by :

F=qvB\sin\theta

Plugging all values above

F=-2\times 10^{-6}\times 5\times 10^6\times 3\times 10^{-4}\times \sin (20)\\\\F=1.02\times 10^{-3}\ N

So, force exerted on a moving charge is 1.02\times 10^{-3}\ N.

4 0
3 years ago
What happens to the gravitational force between two objects if the distance between them triples?
joja [24]
So as two objects are separated from each other, the force of gravitational attraction between them also decreases. ... If the separation distance between any two objects is tripled (increased by a factor of 3), then the force of gravitational attraction is decreased by a factor of 9 (3 raised to the second power).

So the answer you are looking for is B.
5 0
2 years ago
Read 2 more answers
A 40kg miniature horse runs west at 8 m/s . What is the force of impact if it hits a fence and comes to a sudden stop in 0.5s?
Andru [333]

Answer:

640 N

Explanation:

Given :

Mass of horse, m = 40kg

initial speed of horse, u = 8 m/s

final speed of horse, v = 0 m/s  (because horse comes to a sudden stop)

time taken to stop, t = 0.5 s

recall that acceleration = change in speed / time taken for the change

or

a = (v - u) / t     (substituting the above values)

a = (0 - 8) / 0.5

a = -16 m/s²   (i.e it is a deceleration of 16 m/s²)

since we are not concerned about the direction of the force, we can simply use the absolute value of acceleration which is a = 16 m/s²

also recall that

Force = mass x acceleration

F = ma    (substituting the values above)

F = 40kg x 16 m/s

F = 640 N

6 0
3 years ago
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