Answer:
There is 18.8% lithium by mass in second sample
Explanation:
Both the two samples are pure lithium carbonate. So % lithium by mass will be same in both samples. This can be proved mathematically as follows-
Let's assume weight of first sample is x g
So, 100 g of sample contains 18.8 g of lithium
Hence, x g of sample contains 
g of lithium
Now, the second sample has weight equal to 2x g
So, 2x g of sample contains 
g of lithium
So, % lithium by mass in second sample = 
% = 18.8%
Answer:
![[Cl^-]=232.3\frac{mgCl^-}{L}](https://tex.z-dn.net/?f=%5BCl%5E-%5D%3D232.3%5Cfrac%7BmgCl%5E-%7D%7BL%7D)
Explanation:
Hello,
In this case, we can represent the chemical reaction as:
In such a way, since the mass of the obtained silver chloride is 93.9 mg, we can compute the chloride ions in the ground water by using the following stoichiometric procedure whereas the molar mass of chloride ions and silver chloride are 35.45 g/mol and 143.32 g/mol respectively:
Finally, for the given volume of water in liters (0.100L), we compute the required concentration:
![[Cl^-]=\frac{23.2mgCl^-}{0.100L}\\](https://tex.z-dn.net/?f=%5BCl%5E-%5D%3D%5Cfrac%7B23.2mgCl%5E-%7D%7B0.100L%7D%5C%5C)
Best regards.
Answer:
Volume
Explanation:
Cubic centimeters are used to measure the space an object takes up, or its volume.
To compute the percent error, you divide the absolute difference between the actual value and the measured value with the actual value. Then, multiply it with 100 to get the percentage. The solution is as follows:
Percent error = (250 - 243.9)/250 * 100
Percent error = 2.44%
D. Both particles and high energy radiation
