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NemiM [27]
3 years ago
9

Iron (III) chloride + sodium carbonate → iron (III) carbonate + sodium chloride Which of these is the balanced equation for the

reaction described above?
Chemistry
1 answer:
Nonamiya [84]3 years ago
4 0
2 FeCl3 + 3 Na2CO3 = Fe2(CO3)3 + 6 NaCl


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Compare and contrast the uses of iron triad and the use of coinage metals
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<span>Answer: Iron triad are used in the process to create steel and other metal mixtures. Coinage Metals are used for much more than just coins, and many other elements besides these are made into coins.</span>
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In which sample of water do the water particles have more energy: 5 grams of ice cubes at -10 degrees Celsius or 5 grams of liqu
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What is the volume of an object with a mass of 220g and a desnisty of 55cm3?
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7 0
3 years ago
Which is denser, a solid solution, a gaseous solution,or a liquid solution
Leto [7]

Answer:

Gaseous solution isn't dense, neither the solid, but liquid is denser

Explanation:

Gas: only gases are dissolved under a given set of conditions.Since interactions between molecules play almost no role, dilute gases form rather trivial solutions. In part of the literature, they are not even classified as solutions, but addressed as mixtures.

Liquid: If the solvent is a liquid, then almost all gases, liquids, and solids can be dissolved.

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7 0
3 years ago
A metal crystallizes in a body-centered cubic unit cell. The radius of one atom = 2.30 x 10 -8 cm. The density of the metal is 0
maw [93]

Answer:

25.41 g/mol is molar mass of metal.

Explanation:

Number of atom in BCC unit cell = Z = 2

Density of metal = 0.867 g/cm^3

Edge length of cubic unit cell= a = ?

Radius  of the atom of metal = r = 2.30\times 10^{-8} cm

a=2\times r=2\times 2.30\times 10^{-8} cm=4.60\times 10^{-8} cm

Atomic mass of metal =M

Formula used :  

\rho=\frac{Z\times M}{N_{A}\times a^{3}}

where,

\rho = density

Z = number of atom in unit cell

M = atomic mass

(N_{A}) = Avogadro's number  

a = edge length of unit cell

On substituting all the given values , we will get the value of 'a'.

0.867 g/cm^3=\frac{2\times M}{6.022\times 10^{23} mol^{-1}\times (4.60\times 10^{-8} cm)^{3}}

M = 25.41 g/mol

25.41 g/mol is molar mass of metal.

6 0
4 years ago
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