20 POINTS / WILL GIVE BRAINLIEST

Mathematics

1 answer:

padilas [110]3 years ago

3 0

Answer: Total Volume = 15π + 18 π= 33π cubic mm

Step-by-step explanation:

What is the volume of the composite figure? Leave the answer in terms of π.

_33π mm3

We have a cone here conjoined to a semi-sphere.

Cone volume: C = (1/3)*(πr^2) * h

semi-sphere volume : V = (1/2)* (4/3) * (π * r^3)

r = 3 mm and h = 5mm

so C = (1/3)*(π (3)^2) * 5 = 15π cubic mm

V = (1/2)* (4/3) * (π * 3^3) = 18 π cubic mm

Total Volume = 15π + 18 π= 33π cubic mm

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NEED HELP will give BRAINLY

LenKa [72]

Answer:

y=1x+8

Step-by-step explanation:

The best way to remember the formula is y=mx+b aka (your mom's ex bf)
Just by looking at the slope you can automatically tell it's moving by one so in your formula, 'm' is the slope.
Add 1x to replace 'm' or you can leave x alone because x is already one, your choice.
b is the indication on where your slope started in the y-axis.
In this case, by looking at the y-axis on the graph, the slope starts at 8 so that will be your b.
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8 0

3 years ago

If the expression 5+2x was evaluated for x=4 it’s value would be

iris [78.8K]

Answer: 13

Step-by-step explanation:

5+2x

When x=4

5+2(4)

5+8

= 13

5 0

3 years ago

Read 2 more answers

part 3. Find the value of the trig function indicated, use Pythagorean theorem to find the third side if you need it.

Nat2105 [25]

Answer: $\bold{9)\ \sin \theta=\dfrac{1}{3}\qquad 10)\ \sin \theta = \dfrac{4}{5}\qquad 11)\ \cos \theta = \dfrac{\sqrt{11}}{6}\qquad 12)\ \tan \theta = \dfrac{17\sqrt2}{26}}$

Step-by-step explanation:

Pythagorean Theorem is: a² + b² = c² , where "c" is the hypotenuse

$9)\ \sin \theta=\dfrac{\text{side opposite of}\ \theta}{\text{hypotenuse of triangle}}=\dfrac{4}{12}\quad \rightarrow \large\boxed{\dfrac{1}{3}}$

Note: 4² + (8√2)² = hypotenuse² → hypotenuse = 12

$10)\ \sin \theta=\dfrac{\text{side opposite of}\ \theta}{\text{hypotenuse of triangle}}=\dfrac{16}{20}\quad \rightarrow \large\boxed{\dfrac{4}{5}}$

Note: 12² + opposite² = 20² → opposite = 16

$11)\ \cos \theta=\dfrac{\text{side adjacent to}\ \theta}{\text{hypotenuse of triangle}}=\dfrac{\sqrt{11}}{6}\quad =\large\boxed{\dfrac{\sqrt{11}}{6}}$

Note: adjacent² + 5² = 6² → adjacent = √11

$12)\ \tan \theta=\dfrac{\text{side opposite of}\ \theta}{\text{side adjacent to}\ \theta}=\dfrac{17}{13\sqrt2}\quad =\large\boxed{\dfrac{17\sqrt2}{26}}$