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3 years ago

6

aluminum has 13 electrons. how many electrons are found in the outermost energy level for this atom which energy level is the ou

termost

2 answers:

Stolb23 [73]3 years ago

8 0

<span>The outermost energy level of an element are called the valence shell, that holds the valence electrons. they consist of the highest energy level. In aluminum, the valence electrons are 3. </span>

Westkost [7]3 years ago

8 0

Those electrons would be called valence electrons. Check the group number. 3 would be the amount in the outermost shell, so those are the valence electrons.

Answer is 3

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19. What gives an atomic nucleus its

lana [24]

Answer: The correct choice is, B: protons

Explanation:

Protons have a positive charge whereas neutrons have no charge and electrons have a negative charge. Due to positive charge of protons, nucleus of an atom acquires a positive charge. Therefore, we can conclude that protons are the particles give the nucleus its positive charge.

3 0

3 years ago

When resting, a person has a metabolic rate of about 3.0 105 joules per hour. The person is submerged neck-deep into a tub conta

jek_recluse [69]

Answer:

The temperature after half an hour is $19.3002^{\circ}$

Solution:

As per the question;

Metabolic rate of the person is 3.0105 J/h

Temperature, T = $19.30^{\circ}$

Mass of the water, $m_{w} = 1.2103 kg$

Time duration, t = 0.5 h = 30 min = 180 s

Now,

Heat, $Q = ms\Delta t$

Thus heat transfer in half an hour:

$Q = 3.0105\times 0.5 = 1.505 J$

Now, the temperature of water after half an hour, T' is given by:

$Q = m_{w}s\Delta T = ms(T' - T)$

where

s = 4186 J

$1.505 = 1.21103\times 4186\times (T' - 19.30^{\circ})$

$T' = 19.3002 ^{\circ}$

4 0

3 years ago

An underground cannon launches a cannonball from ground level at a 35 degree angle. the cannonball is shot with an initial veloc

user100 [1]

Answer:

Time = 1.75[s]; Distance traveled = 21.5 [m]; Max height = 15 [m]

Explanation:

First, we have to break down the velocity vector into the X & y components.

$(v_{x})_{0} = 15 * cos( 35)= 12.28[m/s]\\(v_{y})_{0} = 15 * sin( 35)= 8.6[m/s]\\\\$

To find the time t that lasts the ball of cannon in the air we must use the following equation of kinematics, in this equation the value of y is equal to zero because it will be proposed that the ball lands at the same level that was fired.

$y=(v_{y} )_{0}-\frac{1}{2}*g*t^{2} \\where:\\g=9.81[m/s^2]\\t = time[s]\\y=0[m]$

$0=8.6*t-\frac{1}{2}*9.81*t^{2} \\4.905*t^{2}=8.6*t\\ t=1.75[s]$

In order to find the distance traveled horizontally from the cannonball, we must use the speed kinematics equation in the X coordinate.

$x = (v_{x})_{0} *t\\x=12.28*1.75\\x=21.5 [m]$

In order to find the last value, we must bear in mind that when the cannonball reaches the maximum height, the velocity in the component y is equal to zero, and we can find the value of and with the following kinematic equation

$y = (v_{y})_{0} *t+\frac{1}{2} *g*(t)^{2} \\y = 0*t+\frac{1}{2} *9.81*(1.75)^{2}\\ y=15 [m]$

6 0

3 years ago

A 2 column table with 2 rows. The first column is labeled material with entries gold, iron. The second column is labeled specifi

topjm [15]

Iron atoms are heavier than gold atoms

Explanation:

Chart:

Materials Specific heat

Gold 0.129

Iron 0.45

The specific heat of a substance is the amount of heat required to raise the temperature of 1g of the substance by 1K.

We can see that the more the mass of a substance, the higher the specific heat needed to raise the temperature.

Specific heat is directly proportional to the mass of substance.

It also dependent on the amount of heat supplied and the nature of the substance.

The mass of a body is the amount of substance it contains.
A heavier substance has more number of atoms in it.
Since iron has a higher specific it, the atoms must be heavier or more than that of gold.

learn more:

Specific heat brainly.com/question/7210400

#learnwithBrainly

8 0

4 years ago

Read 2 more answers

As part of an interview for a summer job with the Coast Guard, you are asked to help determine the search area for two sunken sh

MrMuchimi

Answer: $37^{\circ}$ North of west

Explanation:

Given

40,000-ton luxury line traveling 20 knots towards west and

60,000 ton freighter traveling towards North with 10 knots

suppose v is the common velocity after collision

conserving momentum in west direction

$20\times 40,000=(20,000+60,000)v\cos \theta$

suppose the final velocity makes \theta angle with x axis

$v\cos \theta =10----1$

Conserving Momentum in North direction

$10\times 60,000=80,000\times v\sin\theta$

$v\sin \theta =\frac{15}{2}----2$

divide 1 and 2

$\tan \theta =\frac{3}{4}$

$\theta =37^{\circ}$

so search in the area $37^{\circ}$ North of west to find the ship

3 0

3 years ago