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Alik [6]
3 years ago
12

Mendeleev noticed that if he organized the elements by atomic weight certain patterns emerged. For instance, elements in the sam

e group (family) appeared to have the same
A) valence.
B) melting point.
C) isotopic ratio.
D) number of neutrons.
Physics
2 answers:
Inga [223]3 years ago
6 0
I've had a similar question on an assignment myself, so I'm going to assume it had the same idea.

When you organize them in such a way, the pattern that emerges tells you elements organized by atomic weight have the same number of valence electrons.

Hope this helps!
lys-0071 [83]3 years ago
5 0

Answer:

Is option A

Explanation:

The correct answer is valence. Our current periodic table puts these elements in the same column on the periodic table. We now know they have the same number of valence electrons.

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Answer:

The answer is "60.74^{\circ}".

Explanation:

Cavity and benzene should be extended in equal quantities.

\to 1.18 \times 10^{-3}\times (1+ \Delta T \times 0.000051) = 1.1\times 10^{-3} \times (1+ \Delta T \times 0.00124)\\\\\to  (\frac{1.18}{1.1})\times (1+ \Delta T \times 0.000051) = 1+ \Delta T \times 0.00124\\\\ \to 1.072\times (1+ \Delta T \times 0.000051) = 1+ \Delta T \times 0.00124\\\\ \to 1.072+ \Delta T \times 0.000054672 = 1+ \Delta T \times 0.00124\\\\ \to 1.072+ \Delta T \times 0.000054672 - 1- \Delta T \times 0.00124=0\\\\

\to 0.072+ \Delta T \times 0.000054672 - \Delta T \times 0.00124=0\\\\ \to 0.072+ \Delta T ( 0.000054672 -0.00124)=0\\\\ \to \Delta T ( 0.000054672 -0.00124)= -0.072\\\\ \to \Delta T = -\frac{0.072}{( 0.000054672 -0.00124)}\\\\ \to \Delta T = -\frac{0.072}{-0.001185328 }\\

\to \Delta T = \frac{0.072}{0.001185328 }\\\\ \to \Delta T = 60.74^{\circ}\\

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