How many ml of 0.01-m naoh will be required to titrate 0.061-g of khp to it's endpoint?

1 answer:

hjlf3 years ago

6 0

The volume of NaOH needed for the titration is calculated by equating the number of moles of KHP and NAOH.

(1) number of moles of KHP:
n = mass of KHP / molar mass of KHP
Substituting,
n = 0.061 g / (204.22 g/mol) = 2.987 x 10⁻⁴ moles KHP

(2) number of moles of NaOH
n = (volume NaOH in L)(molarity of NaOH)
n = V x 0.01

Equating,
0.01V = 2.987 x 10⁻⁴

The value of V from the equation is 0.0299L of NaOH.

Converting the value to mL will give us the answer of 29.87 mL.

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