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Marat540 [252]
3 years ago
10

How many ml of 0.01-m naoh will be required to titrate 0.061-g of khp to it's endpoint?

Chemistry
1 answer:
hjlf3 years ago
6 0
The volume of NaOH needed for the titration is calculated by equating the number of moles of KHP and NAOH.

(1) number of moles of KHP:
         n = mass of KHP / molar mass of KHP
Substituting,
         n = 0.061 g / (204.22 g/mol) = 2.987 x 10⁻⁴ moles KHP

(2) number of moles of NaOH
         n = (volume NaOH in L)(molarity of NaOH)
          n = V x 0.01

Equating,
       0.01V = 2.987 x 10⁻⁴

The value of V from the equation is 0.0299L of NaOH. 

Converting the value to mL will give us the answer of 29.87 mL. 
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The new pressure of the gas that initially have a pressure of 853.0 millibars at a temperature of 29.0 °C is 1011.17 millibars. Details about pressure can be found below.

<h3>How to calculate pressure?</h3>

The pressure of a given gas can be calculated using the following formula:

P1/T1 = P2/T2

Where;

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Therefore, the new pressure of the gas that initially have a pressure of 853.0 millibars at a temperature of 29.0 °C is 1011.17 millibars.

Learn more about pressure at: brainly.com/question/15175692

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