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STALIN [3.7K]
3 years ago
8

Chemical reactions will occur if the products are less stable than the reactants. true or false

Chemistry
1 answer:
rusak2 [61]3 years ago
8 0
For the answer to the question above, Chemical reactions will occur if the products are less stable than the reactants

<span>So, the answer to your question is True.
I hope my answer helped you. Feel free to ask more questions. Have a nice day!</span>
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The volume of a gas at 5.0 atm is 3.5 L. What is the volume of the gas at 7.0 atm at the same temperature?
Gemiola [76]

Answer:

2.5 L.

Explanation:

  • We can use the general law of ideal gas: <em>PV = nRT.</em>

where, P is the pressure of the gas in atm.

V is the volume of the gas in L.

n is the no. of moles of the gas in mol.

R is the general gas constant,

T is the temperature of the gas in K.

  • If n and T are constant, and have two different values of V and P:

<em>P₁V₁ = P₂V₂ </em>

P₁ = 5.0 atm, V₁ = 3.5 L.

P₂ = 7.0 atm, V₂ = ??? L.

<em>∴ V₂ = P₁V₁/P₂ </em>= (5.0 atm)(3.5 L)/(7.0 atm) = <em>2.5 L. </em>

6 0
4 years ago
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PLEASE HELP ASAP
Kisachek [45]

Answer:

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Explanation:

A series of chemical reactions transform Volatile Organic Compounds (VOCs) into substances that combine with nitrogen dioxide to produce PAN (Peroxyacytyl nitrate), yet another element in smog. Nitrogen dioxide in the air also reacts with water vapor to form nitric acid, one of the types of acid in acid rain.

6 0
3 years ago
Given the equation representing a system at equilibrium:Which statement describes the concentration of the two gases in this sys
WARRIOR [948]

Answer:

.The concentration of N2O4(g) and the concentration of NO2(g) must be constant.

Explanation:

N2O4(g)<--------> 2NO2(g)

At equilibrium, all the concentrations of species involved in the equilibrium expression remain constant. This is because, at equilibrium, the rate of forward reaction equals the rate of reverse reaction. The concentration of the system does not change with time. The relative concentration of each specie, remain steady at equilibrium.

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3 years ago
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Answer:

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Explanation:

6 0
3 years ago
What is the molarity of a naoh solution if 28.2 ml of a 0.355 m h2so4 solution is required to neutralize a 25.0-ml sample of the
Mrac [35]

Answer;

Molarity of NaOH is 0.80 M

Explanation;

The balanced equation for the reaction is;

2NaOH(aq) + H2SO4(aq = NaSO4(aq) +2 H2O (l)

Moles = concentration x volume  

thus; 0.355M x 0.0282L= 0.01 moles of H2SO4.

Using the mole ratio;

Moles of NaOH = Moles of H2SO4 ×2

                         = 0.02 Moles

Therefore; moles of NaOH = 0.02 moles

But; Concentration = moles / volume  

Thus; Concentration of NaOH = 0.02 / 0.025L

                                       = 0.8M


4 0
3 years ago
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