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3 years ago

Need help with matching the pictures with biomes

Chemistry

2 answers:

vitfil [10]3 years ago

7 0

Answer:

what picture

Explanation:

b DH dhdhdhdh

never [62]3 years ago

6 0

There’s no imageee attached

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Pathogens grow well in food that has a temperature between

ad-work [718]

Answer:

freeze da food

Explanation:

cuz if u freeze it it turns cold

3 0

3 years ago

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Which of the following represents a synthesis reaction?

bija089 [108]

Answer: a) 2H2 + O2 --> 2H2O

Explanation: 2 compounds are combining to form a new compound. The others have 2 substances as the end result and synthesis only produces one result (2H2O in this case)

6 0

3 years ago

If the half-life of 37Rb is 4.7x101 years, how long would it take for 0.5 grams of a 2 gram sample to radioactively decay?

k0ka [10]

<u>Answer:</u> The time required will be 19.18 years

<u>Explanation:</u>

All the radioactive reactions follows first order kinetics.

The equation used to calculate half life for first order kinetics:

$k=\frac{0.693}{t_{1/2}}$

We are given:

$t_{1/2}=4.7\times 10^1yrs$

Putting values in above equation, we get:

$k=\frac{0.693}{4.7\times 10^1yr}=0.015yr^{-1}$

Rate law expression for first order kinetics is given by the equation:

$k=\frac{2.303}{t}\log\frac{[A_o]}{[A]}$

where,

k = rate constant = $0.015yr^{-1}$

t = time taken for decay process = ?

$[A_o]$ = initial amount of the reactant = 2 g

[A] = amount left after decay process = (2 - 0.5) = 1.5 g

Putting values in above equation, we get:

$0.015yr^{-1}=\frac{2.303}{t}\log\frac{2}{1.5}\\\\t=19.18yrs$

Hence, the time required will be 19.18 years

4 0

3 years ago

123.0 x 12.35 / (0.05 x 6.049) significant figures

VMariaS [17]

Answer:

123.0*12.35/(0.05*6.049)

first do in small bracket 123.0*12.35/0.30245

and then divide 123.0*40.83319557

and multiply 5022.483055

6 0

3 years ago

Given that the ionizable h atoms are associated with carboxyl groups, draw a plausible structure for maleic acid. draw the molec

NeTakaya

The structure of maleic acid and its ionized form :

7 0

4 years ago

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